Question

Marcos and 16 coins in nickels and quarters. He has 3 more quarters than nickels. Write the system of equations and solve to find the number of nickels and the number of quarters Marcos has.

Answer 1

There is typo error in the question. The total number of coins will be 15.

Answer:

There are 6 nickels and 9 quarters.

Step-by-step explanation:

Let 'n' be number of nickels and 'q' be number of quarters.

Given:

Marcos has 15 coins in total.

Marcos has 3 more quarters than nickels.

So, as per question,

Total coins = Number of nickels + Number of quarters.

Framing in equation form, we get:

$n+q=15$ ------------------ (1)

Now, Marcos has 3 more quarters than nickels. So, framing in equation form, we get:

$q=3+n$ -------------------- (2)

Substitute the value of 'q' from equation (2) to equation (1). This gives,

$n+3+n=15\\2n=15-3\\2n=12\\n=\frac{12}{2}=6$

Therefore, the number of nickels are 6.

Now, number of quarters = 6 + 3 = 9

So, there are 6 nickels and 9 quarters.