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kifflom [539]
3 years ago
13

Which statement about the slope of the line is true?

Mathematics
1 answer:
givi [52]3 years ago
3 0

Answer:

A

Step-by-step explanation:

sorry I don't kwon how to put it in, in explaination

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Suppose that you were not given the sample mean and sample standard deviation and instead you were given a list of data for the
Troyanec [42]

Answer:

So, the sample mean is 31.3.

So, the sample standard deviation is 6.98.

Step-by-step explanation:

We have a list of data for the speeds (in miles per hour) of the 20 vehicles. So, N=20.

We calculate the sample mean :

\mu=\frac{19 +19 +22 +24 +25 +27 +28+ 37 +35 +30+ 37+ 36+ 39+ 40+ 43+ 30+ 31+ 36+ 33+ 35}{20}\\\\\mu=\frac{626}{20}\\\\\mu=31.3

So, the sample mean is 31.3.

We use the formula for a sample standard deviation:

\sigma=\sqrt{\frac{1}{N-1}\sum_{i=1}^{N}(x_i-\mu)^2}

Now, we calculate the sum

\sum_{i=1}^{20}(x_i-31.3)^2=(19-31.3)^2+(19-31.3)^2+(22-31.3)^2+(24-31.3)^2+(25-31.3)^2+(27-31.3)^2+(28-31.3)^2+(37-31.3)^2+(35-31.3)^2+(30-31.3)^2+(37-31.3)^2+(36-31.3)^2+(39-31.3)^2+(40-31.3)^2+(43-31.3)^2+(30-31.3)^2+(31-31.3)^2+(36-31.3)^2+(33-31.3)^2+(35-31.3)^2\\\\\sum_{i=1}^{20}(x_i-31.3})^2=926.2\\

Therefore, we get

\sigma=\sqrt{\frac{1}{N-1}\sum_{i=1}^{N}(x_i-\mu)^2}\\\\\sigma=\sqrt{\frac{1}{19}\cdot926.2}\\\\\sigma=6.98

So, the sample standard deviation is 6.98.

3 0
2 years ago
Work out the height of a parallelogram of base 10m and area 60m2
Mandarinka [93]

Answer:

600

Step-by-step explanation:

because 60x10=600

3 0
2 years ago
Read 2 more answers
−2/3(3x−4)+3x=5/6 whoever gets right gets brainlyest
REY [17]

−2/3(3x−4)+3x=5/6

= -11/6

7 0
3 years ago
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The test score for a class pf 101 students are computed. What is the percentage of score equal to or grater than the third quart
irina [24]

Answer:

Step-by-step explanation:

The third quartile is at  75% of  total of number of students.

So percentage score great or equal to this is 25%.

4 0
1 year ago
The minimum number of rigid transformations required to show that polygon ABCDE is congruent to polygon FGHIJ is 1 2 3 4 . A rot
MaRussiya [10]
I found the corresponding image. Pls. see attachment.

<span>The minimum number of rigid transformations required to show that polygon ABCDE is congruent to polygon FGHIJ is 2 (translation and rotation).

A rotation translation must be used to make the two polygons coincide.

A sequence of transformations of polygon ABCDE such that ABCDE does not coincide with polygon FGHIJ is a translation 2 units down and a 90° counterclockwise rotation about point D </span>

8 0
2 years ago
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