Answer:
The top one is (3x−2)(x+5)
the bottom one is (3x−2)(3x+2)
Step-by-step explanation:
(2x + 3y = 12) x (-2)
(4x - 3y = 6) x 1
-4x - 6y = -24
4x - 3y = 6
You can cancel out the x values by adding the two equations together.
(-4x + 4x) + (-6y - 3y) = (-24 + 6)
-9y = -18
y = 2
Solve for x now...
4x - 3(2) = 6
4x - 6 = 6
4x = 12
x = 3
Check... (x = 3, y = 2)
2(3) + 3(2) = 12
6 + 6 = 12
12 = 12 <- this works!
4(3) - 3(2) = 6
12 - 6 = 6
6 = 6 <- this works!
Answer: y = (3/2)x
m = 3/2 is the slope
(x1,y1) = (0,0) is the point we want the line to go through, aka the origin
Use point slope form, plug in the given values, and convert to slope intercept form
y - y1 = m(x - x1) .... point slope form
y - 0 = (3/2)*(x - 0) .... substitution
y = (3/2)x .... final answer in slope intercept form
