The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
</span>
Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
Answer:
x=12
Step-by-step explanation:
1/2x - 5 = 10 - 3/4x ---> move like terms to the same side
1/2x + 3/4x = 10 + 5 ---> calculate
5/4x = 15 ---> multiply both sides by 4/5
x = 12
Exponents if those are the answer it bc the second number is an exponent
3^3= 27
4^3=64
3^4=81
Answer:
Its different.
Step-by-step explanation:
Henry's garden:
divide 24 and 18 by 6: you get 4:3 ratio of tomato:green bean
Simon's garden:
divide both 30 and 25 by 5: you get 6:5 ratio of tomato:green bean.
Answer:Use this PEMDAS to solve
Step-by-step explanation:
Parethiesis,Exponent,Multiplication,Division,Addition,and Subtraction.
ALWAYS DO P FIRST!!!!
