The probability of getting all heads is 1 / 2^6 = 1/64 as there is only 1 event where this happens in a possible 2^6 = 64 events. It is the same as the probability of getting all tails. The probability of getting at least 1 head is 1 - p(all tails) = 63/64.
The answer is <span>A –x^2 + 3x + 15
</span>
3x² + 6 – 2x + 5x – 4x²<span> + 9
Rearrange it:
</span>3x² + 6 – 2x + 5x – 4x² + 9
= 3x² - 4x² - 2x + 5x + 6 + 9
= -x² + 3x + 15
