Ask question

Ask question

All categories

3 years ago

5

The actual length of the rectangle below is 41 cm. Using the scale drawing below, find the actual width.

2 answers:

Margaret [11]3 years ago

7 0

Okay, so your scale rectangle has a length of l = 8.2 cm. The actual triangle has a length of L = 41 cm. What is the scale factor? You find out by dividing the scale rectangle l from the actual rectangle L.

41 cm / 8.2 cm = 5

The scale factor is 5. That means the actual rectangle is exactly 5 times bigger than the scale rectangle. Now finding the width is easy! If the width of the scale rectangle is 2.1 cm and the scale factor is 5, you just multiply them together!

2.1 cmx 5 = 10.5 cm

The width of the actual rectangle is 10.5 cm! Hope that helps!

yaroslaw [1]3 years ago

4 0

Answer:

The width of the actual rectangle is 10.5 cm

Step-by-step explanation:

You might be interested in

What is the cube if 8?

vlada-n [284]

The cube root of 8 is 2.

8 0

3 years ago

Help with 21 would be much appreciated.

umka2103 [35]

Answer:

$\large\boxed{x=2\sqrt{21}\ and\ y=4\sqrt3}$

Step-by-step explanation:

Look at the picture.

ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

$\dfrac{AD}{CD}=\dfrac{CD}{DB}$

We have

$AD=14-8=6\\CD=y\\DB=8$

Substitute:

$\dfrac{6}{y}=\dfrac{y}{8}$ <em>cross multiply</em>

$y^2=(6)(8)$

$y^2=48\to y=\sqrt{48}\\\\y=\sqrt{16\cdot3}\\\\y=\sqrt{16}\ cdot\sqrt3\\\\\boxed{y=4\sqrt3}$

For x use the Pythagorean theorem:

$x^2=6^2+(4\sqrt3)^2\\\\x^2=36+48\\\\x^2=84\to x=\sqrt{84}\\\\x=\sqrt{4\cdot21}\\\\x=\sqrt4\cdot\sqrt{21}\\\\\boxed{x=2\sqrt{21}}$

3 0

3 years ago

astra-53 [7]

Answer:

2+i times the square root of 7

4 0

3 years ago

Read 2 more answers

What is a 3-dimensional shape made of two identical circles connected by a rectangle

nekit [7.7K]

Answer:

cylinder

Step-by-step explanation:

5 0

3 years ago

Two fifteenths times 10

Ahat [919]

Answer:

1.3

Step-by-step explanation:

6 0

3 years ago