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mafiozo [28]
3 years ago
5

The actual length of the rectangle below is 41 cm. Using the scale drawing below, find the actual width.

Mathematics
2 answers:
Margaret [11]3 years ago
7 0

Okay, so your scale rectangle has a length of l = 8.2 cm. The actual triangle has a length of L = 41 cm. What is the scale factor? You find out by dividing the scale rectangle l from the actual rectangle L.

41 cm / 8.2 cm = 5

The scale factor is 5. That means the actual rectangle is exactly 5 times bigger than the scale rectangle. Now finding the width is easy! If the width of the scale rectangle is 2.1 cm and the scale factor is 5, you just multiply them together!

2.1 cmx 5 = 10.5 cm

The width of the actual rectangle is 10.5 cm! Hope that helps!

yaroslaw [1]3 years ago
4 0

Answer:

The width of the actual rectangle is 10.5 cm

Step-by-step explanation:

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Hello!

288 / 24 = 12

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3 years ago
Multiply.
Crank
The main rules that we use here are :

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ii) \sqrt{a} \cdot  \sqrt{a} =a.


Thus, first 'decompose' the numbers in the radicals into prime factors:

4 \sqrt{3} \cdot 10 \cdot  \sqrt{2\cdot2\cdot3}\cdot  \sqrt{2\cdot 3}\cdot  \sqrt{2}..

By rule (i) we write:

4 \sqrt{3} \cdot 10 \cdot \sqrt{2}\cdot \sqrt{2}\cdot \sqrt{\cdot3}\cdot \sqrt{2} \cdot  \sqrt{3} \cdot \sqrt{2}.

We can collect these terms as follows:

40 \sqrt{3}\cdot (\sqrt{3}\cdot \sqrt{3}) \cdot (\sqrt{2}\cdot \sqrt{2}) \cdot( \sqrt{2} \cdot \sqrt{2}), and by rule (ii) we have:

40 \sqrt{3}\cdot 3 \cdot 2 \cdot2=40\cdot12\cdot \sqrt{3}=480 \sqrt{3}.


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8 0
4 years ago
The cake store is having a 25% off sale on all of its cakes.
Shalnov [3]

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Step-by-step explanation:

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4 0
3 years ago
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The price p in dollars and the quantity x sold of a certain product obey the demand equation -1/5x+100 (0≤ x ≤ 500)
olga nikolaevna [1]

Answer:

  • See below

Step-by-step explanation:

<u>We have:</u>

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c) <u>This is a quadratic function and the maximum value is obtained at vertex.</u>

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d) <u>The max revenue is obtained when -0.2x + 100 at max:</u>

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9. In the figure below, the area of Square 1 is
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