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eimsori [14]
3 years ago
15

Can you do a composition of transformation in any order? Why or why not?

Mathematics
1 answer:
Fynjy0 [20]3 years ago
8 0

Answer:

You can compose any transformations, but here are some of the most common compositions.

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Example of inverse operation
luda_lava [24]
Examples of inverse operations are addition and subtraction or multiplication and division.
6 0
4 years ago
Show work please !!!
aleksklad [387]

Answer:

512x⁴y¹²

Step-by-step explanation:

its a cube so length x width x height

8xy⁴ times 8xy⁴ times 8xy⁴ is 512x³y¹²

5 0
3 years ago
The College Board SAT college entrance exam consists of three parts: math, writing and critical reading (The World Almanac 2012)
Wittaler [7]

Answer:

Yes, there is a difference between the population mean for the math scores and the population mean for the writing scores.

Test Statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1 .

Step-by-step explanation:

We are provided with the sample data showing the math and writing scores for a sample of twelve students who took the SAT ;

Let A = Math Scores ,B = Writing Scores  and D = difference between both

So, \mu_A = Population mean for the math scores

       \mu_B = Population mean for the writing scores

 Let \mu_D = Difference between the population mean for the math scores and the population mean for the writing scores.

            <em>  Null Hypothesis, </em>H_0<em> : </em>\mu_A = \mu_B<em>     or   </em>\mu_D<em> = 0 </em>

<em>      Alternate Hypothesis, </em>H_1<em> : </em>\mu_A \neq  \mu_B<em>      or   </em>\mu_D \neq<em> 0</em>

Hence, Test Statistics used here will be;

            \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1    where, Dbar = Bbar - Abar

                                                               s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}}

                                                               n = 12

Student        Math scores (A)          Writing scores (B)         D = B - A

     1                      540                            474                                   -66

     2                      432                           380                                    -52  

     3                      528                           463                                    -65

     4                       574                          612                                      38

     5                       448                          420                                    -28

     6                       502                          526                                    24

     7                       480                           430                                     -50

     8                       499                           459                                   -40

     9                       610                            615                                       5

     10                      572                           541                                      -31

     11                       390                           335                                     -55

     12                      593                           613                                       20  

Now Dbar = Bbar - Abar = 489 - 514 = -25

 Bbar = \frac{\sum B_i}{n} = \frac{474+380+463+612+420+526+430+459+615+541+335+613}{12}  = 489

 Abar =  \frac{\sum A_i}{n} = \frac{540+432+528+574+448+502+480+499+610+572+390+593}{12} = 514

 ∑D_i^{2} = 22600     and  s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}} = \sqrt{\frac{22600 - 12*(-25)^{2} }{12-1} } = 37.05

So, Test statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1

                            = \frac{-25 - 0}{\frac{37.05}{\sqrt{12} } } follows t_1_1   = -2.34

<em>Now at 5% level of significance our t table is giving critical values of -2.201 and 2.201 for two tail test. Since our test statistics doesn't fall between these two values as it is less than -2.201 so we have sufficient evidence to reject null hypothesis as our test statistics fall in the rejection region .</em>

Therefore, we conclude that there is a difference between the population mean for the math scores and the population mean for the writing scores.

8 0
3 years ago
Need help with this question plz.Will Give BRAINLIEST
Ierofanga [76]
For the first one his car used 8/340 or 2/85 gallons for one mile.

After the fix, his car 7/350 or 1/50 gallons for one mile.

Then you subtract 1/50-2/85 to get (17-10)/850 or 7/850.

You multiply this by 4 to get 28/850 which is $0.0329411

Since it is asking for cents you multiply by 100 to get approximately 3 cents.
5 0
3 years ago
If f(x)=2x²-x find f(-3)
ivolga24 [154]

Answer:

21

Step-by-step explanation:

f(x) = 2x^2 - x

f(-3) = 2*(-3)^2 - (-3)

=2*9 +3

=18 +3

=21

3 0
3 years ago
Read 2 more answers
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