Question

Solve for N. 2[7-6(1-n)]+3n=-20+4[6(n+1)-3n]

Answer 1

Solving the expression $2[7-6(1-n)]+3n=-20+4[6(n+1)-3n]$ we get  $n=\frac{2}{3}$

Step-by-step explanation:

We need to solve the equation $2[7-6(1-n)]+3n=-20+4[6(n+1)-3n]$ and find value of n.

Solving:

$2[7-6(1-n)]+3n=-20+4[6(n+1)-3n]$

Multiplying the terms inside the bracket

$2[7-6+6n]+3n=-20+4[6n+6-3n]$

Simplifying:

$2[1+6n]+3n=-20+4[6n-3n+6]$

$2[1+6n]+3n=-20+4[3n+6]$

$2+12n+3n=-20+12n+24$

$2+15n=12n+4$

Adding -12n and -2 on both sides

$15n-12n=4-2$

$3n=2$

$n=\frac{2}{3}$

So, Solving the expression $2[7-6(1-n)]+3n=-20+4[6(n+1)-3n]$ we get  $n=\frac{2}{3}$

Keywords: Solving Equations

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