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AURORKA [14]
3 years ago
9

I need the answer to solve this I’ve been stuck all day

Mathematics
1 answer:
Ludmilka [50]3 years ago
8 0
The surface area of it is 164 because you multiply each side by the length of the height and width and then add them all together
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To take the neighbor's children to the
madam [21]

Answer:

h>27

Step-by-step explanation:

process of elimination on numbers I'm assuming this is not requiring decimals

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Simplify 20+16➗2<br><br><br> Please answer ASAP
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28, trust me

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Klio2033 [76]

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  • Commutative

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Multiplication is Commutative. the term can be multiplied in either order. the product will be the same as the previous product.

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8 0
3 years ago
The sum of the measures of the interior angles of a polygon is 720°. How many sides does the polygon have?
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4 0
3 years ago
colby and jaquan are growing bacteria in an experiment in a laboratory. Colby starts with 50 bacteria in his culture and the num
kaheart [24]
To get started, we will use the general formula for bacteria growth/decay problems:

A_{f} =  A_{i} ( e^{kt} )

where: 
A_{f} = Final amount
A_{i} = Initial amount
k = growth rate constant
t = time


For doubling problems, the general formula can be shortened to:

kt = ln(2)

Now, we can use the shortened formula to calculate the growth rate constant of both bacteria:

Colby (1):
k_{1} = ln(2)/t
k_{1} = ln(2)/2 = 0.34657 per hour

Jaquan (2):
k_{2} = ln(2)/t
k_{2} = ln(2)/3 = 0.23105 per hour

Using Colby's rate constant, we can use the general formula to calculate for Colby's final amount after 1 day (24 hours).

Note: All units must be constant, so convert day to hours.

A_{f1} = 50( e^{0.34657(24)})
A_{f1} = 204,800

Remember that the final amount for both bacteria must be the same after 24 hours. Again, using the general formula, we can calculate the initial amount of bacteria that Jaquan needs:

A_{f2} = 204,800 =  A_{i2} ( e^{0.23105(24)} )
A_{i2} = 800

3 0
3 years ago
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