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tigry1 [53]
3 years ago
12

9,6,3,0,-3,-6 work out the nth term (it decrease by the same amount each time)

Mathematics
2 answers:
Shkiper50 [21]3 years ago
8 0

Answer:

-3n+11 or 3n+11 or 3n-11 one of those

Step-by-step explanation:

Luba_88 [7]3 years ago
3 0

Answer:

The answer is -3n+12

Step-by-step explanation:

It is because you do 9+3 and it is positive so it will be positive 12 (+12).

We got -3n from taking away -3 all the way.

I hope you got help

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Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va
Burka [1]

Answer:

\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}

The polynomial is an approximation with an error less than or equals to <em>0.002652</em> for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)

with

\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}

for some c in the interval (-x, x)

In the particular case f

<em>f(x)=cos(x) </em>

<em> </em>

we have

\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)

therefore

\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0

and the polynomial approximation of T5(x) of cos(x) would be

\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}

for some c in (-x,x). So

\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}

and we must find the values of x for which

\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652

Working this inequality out, we find

\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

8 0
3 years ago
A hat is originally priced at $28 is on sale for $15% off. What is the total cost of the hat if the tax is 6.75%?
vampirchik [111]
You do 28, which is the original cost, then you take that 15% off to do that you multiply 28×.15 and you get 4.2 and subtract that from original cost and you get 23.8 then to get the cost after tax you do 23.8×.0675 and you get 1.6 then you add that to 23.8 and get 25.4 dollars
5 0
4 years ago
Jorge has his own business as a painter. The amounts he made in the last five months are shown below. Find the mean, median, and
deff fn [24]

I'm gonna assume that the 5s are $.

To find the mean, add all the numbers, then divide by the number of data points (5).

(2426+2463+1451+2154+1119)/5 = 1922.6

To find the median, put the data in order from least to greatest, then find the middle data point.

1119 1451 2154 2426 2463

To find the range, subtract the largest from the smallest:

2463-1119 = 1344

6 0
4 years ago
elve disks with the given measurements are stacked on top of each other. Which expression does NOT give the volume of the cylind
slava [35]
I don't even know for real 


8 0
3 years ago
Read 2 more answers
Determine the quadrant(s) in which (x, y) could be located. (Select all that apply.)
djyliett [7]

Answer: D. Quadrant IV

Step-by-step explanation: Numbers with a positive or negative sign are referred to be directed numbers. These numerals are easily found on the number line. 2, 5, -1, -3, -7, 9, and so on are some examples.

As a result: x > 0 and y 0 are both true.

Consider the case of specific directed numbers for x and y. Assume x = 5 and y = -2, and the following is true: (5, -2). In a Cartesian plane, this point can be found in the fourth quadrant.

As a result, in a Cartesian plane, the quadrant in which (x, y) might be found is Quadrant IV.

7 0
3 years ago
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