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tigry1 [53]
3 years ago
12

9,6,3,0,-3,-6 work out the nth term (it decrease by the same amount each time)

Mathematics
2 answers:
Shkiper50 [21]3 years ago
8 0

Answer:

-3n+11 or 3n+11 or 3n-11 one of those

Step-by-step explanation:

Luba_88 [7]3 years ago
3 0

Answer:

The answer is -3n+12

Step-by-step explanation:

It is because you do 9+3 and it is positive so it will be positive 12 (+12).

We got -3n from taking away -3 all the way.

I hope you got help

You might be interested in
DF bisects EDG Find FG. The diagram is not to scale.<br><br>A.15<br>B.14<br>C.19<br>D. 28​
Ahat [919]

Answer:

○ b. 14

Step-by-step explanation:

Since <em>DF</em><em> </em>is a segment bisector, set both expressions equal to each other:

3n - 4 = n + 8

-3n - 3n

__________

−4 = −2n + 8

-8 - 8

_________

−12 = −2n

__ ___

−2 −2

6 = n [Plug this back into both expressions above to get the value of 14]; 14 = FG; 14 = EF

I am joyous to assist you anytime.

6 0
3 years ago
What is the midpoint of the segment show below?
slega [8]
B is the answer because if u subtact both x and y
3 0
3 years ago
Read 2 more answers
6) Aisha uses 2 meters of thread for every three squares that she se
Serggg [28]

Answer:

57 squares

Step-by-step explanation:

38/2=19

19*3=57

3 0
3 years ago
Read 2 more answers
Help please solve<br> <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1
Shkiper50 [21]

Answer:

\displaystyle  -\frac{1}{2} \leq x < 1

Step-by-step explanation:

<u>Inequalities</u>

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0

Simplifying by x-1 and taking x=1 out of the possible solutions:

\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

(6x^3+14x^2+10x+12)

is always positive and doesn't affect the result. It can be neglected. The expression

(x-\frac{1}{2})^2

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0

For the expression to be negative, both signs must be opposite, that is

(x+\frac{1}{2})\geq 0, (x-1)

Or

(x+\frac{1}{2})\leq 0, (x-1)>0

Note we have excluded x=1 from the solution.

The first inequality gives us the solution

\displaystyle  -\frac{1}{2} \leq x < 1

The second inequality gives no solution because it's impossible to comply with both conditions.

Thus, the solution for the given inequality is

\boxed{\displaystyle  -\frac{1}{2} \leq x < 1 }

7 0
3 years ago
Amy has 2 rows of 4 sports trophies on each of her 3 shelves. how many trophies does she have in all?
sleet_krkn [62]

Each shelf holds 8 trophies (2X4=8).  3 shelves times 8 trophies will equal a total of 24 trophies.
7 0
3 years ago
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