Answer:
The polynomial is an approximation with an error less than or equals to <em>0.002652</em> for x in the interval
[-1.113826815, 1.113826815]
Step-by-step explanation:
According to Taylor's theorem
with
for some c in the interval (-x, x)
In the particular case f
<em>f(x)=cos(x)
</em>
<em>
</em>
we have
therefore
and the polynomial approximation of T5(x) of cos(x) would be
In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that
for some c in (-x,x). So
and we must find the values of x for which
Working this inequality out, we find
![\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815](https://tex.z-dn.net/?f=%5Cbf%20%5Cdisplaystyle%5Cfrac%7B%7Cx%7C%5E6%7D%7B6%21%7D%5Cleq0.002652%5CRightarrow%20%7Cx%7C%5E6%5Cleq1.90944%5CRightarrow%5C%5C%5C%5C%5CRightarrow%20%7Cx%7C%5Cleq%5Csqrt%5B6%5D%7B1.90944%7D%5CRightarrow%20%7Cx%7C%5Cleq1.113826815)
Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval
[-1.113826815, 1.113826815]
You do 28, which is the original cost, then you take that 15% off to do that you multiply 28×.15 and you get 4.2 and subtract that from original cost and you get 23.8 then to get the cost after tax you do 23.8×.0675 and you get 1.6 then you add that to 23.8 and get 25.4 dollars
I'm gonna assume that the 5s are $.
To find the mean, add all the numbers, then divide by the number of data points (5).
(2426+2463+1451+2154+1119)/5 = 1922.6
To find the median, put the data in order from least to greatest, then find the middle data point.
1119 1451 2154 2426 2463
To find the range, subtract the largest from the smallest:
2463-1119 = 1344
Answer: D. Quadrant IV
Step-by-step explanation: Numbers with a positive or negative sign are referred to be directed numbers. These numerals are easily found on the number line. 2, 5, -1, -3, -7, 9, and so on are some examples.
As a result: x > 0 and y 0 are both true.
Consider the case of specific directed numbers for x and y. Assume x = 5 and y = -2, and the following is true: (5, -2). In a Cartesian plane, this point can be found in the fourth quadrant.
As a result, in a Cartesian plane, the quadrant in which (x, y) might be found is Quadrant IV.
