Answer:
7 / 15
Step-by-step explanation:
15x - 7 = 0
15x = 7
x = 7/15
Answer:
Bob = 6km/h, Joe = 4km/h
Step-by-step explanation:
Bob walked 6km/h after 3 hours = 18 km
Joe walked 4km/h after 3 hours = 12 km
Finally, their distance is 30 km.
Answer:
The equation for a is 
The altitute is 101,428.57 feet
Step-by-step explanation:
You know that the relationship between ground temperature and atmospheric temperature can be described by the formula
t = -0.0035a +g
where:
- t is the atmospheric temperature in degrees Fahrenheit
- a is the altitude, in feet, at which the atmospheric temperature is measured
- g is the ground temperature in degrees Fahrenheit.
Solving the equation for a:
-0.0035a +g=t
-0.0035a= t - g
<u><em>The equation for a is </em></u><u><em></em></u>
If the atmospheric temperature is -305 °F and the ground temperature is 50 °F, then t= -305 °F and g= 50 °F
Replacing in the equation for a you get:
a= 101,428.57
<u><em>The altitute is 101,428.57 feet</em></u>
30°, 70°, and 80°.
It is an acute-angled triangle.
Explanation:
The ratio of the measures of ∠s in Δ is 3:7:8.
So, let us suppose that the measures are, 3k, 7k, 8k.
Evidently, their sum is
180°.
3k+7k+8k=180
18k=180
k= 10
Hence, the measures are,
30°, 70°, and 80°.
As all the angles are acute, so is the triangle.
<span>The two points that are most distant from (-1,0) are
exactly (1/3, 4sqrt(2)/3) and (1/3, -4sqrt(2)/3)
approximately (0.3333333, 1.885618) and (0.3333333, -1.885618)
Rewriting to express Y as a function of X, we get
4x^2 + y^2 = 4
y^2 = 4 - 4x^2
y = +/- sqrt(4 - 4x^2)
So that indicates that the range of values for X is -1 to 1.
Also the range of values for Y is from -2 to 2.
Additionally, the ellipse is centered upon the origin and is symmetrical to both the X and Y axis.
So let's just look at the positive Y values and upon finding the maximum distance, simply reflect that point across the X axis. So
y = sqrt(4-4x^2)
distance is
sqrt((x + 1)^2 + sqrt(4-4x^2)^2)
=sqrt(x^2 + 2x + 1 + 4 - 4x^2)
=sqrt(-3x^2 + 2x + 5)
And to simplify things, the maximum distance will also have the maximum squared distance, so square the equation, giving
-3x^2 + 2x + 5
Now the maximum will happen where the first derivative is equal to 0, so calculate the first derivative.
d = -3x^2 + 2x + 5
d' = -6x + 2
And set d' to 0 and solve for x, so
0 = -6x + 2
-2 = -6x
1/3 = x
So the furthest point will be where X = 1/3. Calculate those points using (1) above.
y = +/- sqrt(4 - 4x^2)
y = +/- sqrt(4 - 4(1/3)^2)
y = +/- sqrt(4 - 4(1/9))
y = +/- sqrt(4 - 4/9)
y = +/- sqrt(3 5/9)
y = +/- sqrt(32)/sqrt(9)
y = +/- 4sqrt(2)/3
y is approximately +/- 1.885618</span>
