Looking at this problem in terms of geometry makes it easier than trying to think of it algebraically.
If you want the largest possible x+y, it's equivalent to finding a rectangle with width x and length y that has the largest perimeter.
If you want the smallest possible x+y, it's equivalent to finding the rectangle with the smallest perimeter.
However, the area x*y must be constant and = 100.
We know that a square has the smallest perimeter to area ratio. This means that the smallest perimeter rectangle with area 100 is a square with side length 10. For this square, x+y = 20.
We also know that the further the rectangle stretches, the larger its perimeter to area ratio becomes. This means that a rectangle with side lengths 100 and 1 with an area of 100 has the largest perimeter. For this rectangle, x+y = 101.
So, the difference between the max and min values of x+y = 101 - 20 = 81.
Answer:
Step-by-step explanation:
<u>Slope-intercept form:</u> y = mx+ b
m = slope
b = y-intercept
<u>Rearrange the equation:</u>
<u>Divide each side by -20:</u>
is your simplified, slope-intercept form equation.
I think its like this
each row has 6 white tiles
8 rows = 48 tiles
48 - 6 = 42
42 x 8 = 336
so 8 rows = 6 white tiles and 42 purple tiles to make 48 tiles so she will need 336 more tiles to make each 8 rows have 48 tiles
hope this helps : )
Y/2=1-x
y=2-2x
y(-2)=2-2(-2)=2+4=6, (-2,6)
So (-2, 6) is an ordered pair from x+y/2=1
