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Stels [109]
3 years ago
8

When a conditional and its converse are true, you can combine as a true.....

Mathematics
1 answer:
WARRIOR [948]3 years ago
6 0
What is the question?

Conditional is a sentence that has "If..., then..."

Converse is the opposite of the coditional

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How can i solve this equation to find x?
34kurt

Answer:

x = 25

Step-by-step explanation:

We know that A and M are on a line, which is 180 degrees, and the little square means 90 degrees. So, ∠RAM = 180 - 90 = 90 degrees.

∠RAM = ∠RAX + ∠XAM

90 = (2x - 10) + (-3x + 125)

Now, simply combine like terms and solve for x:

90 = 2x - 3x - 10 + 125

90 = -x + 115

x = 115 - 90 = 25

Thus, x = 25.

<em>~ an aesthetics lover</em>

5 0
3 years ago
Read 2 more answers
The radius of a cylinder is measured in meters what unit will the surface area be measured in
iren2701 [21]
<h3>Answer: A) Square meters</h3>

Explanation:

Imagine that a parent bought a basketball for their son or daughter. If they wrapped the ball with wrapping paper, then that wrapping paper can be unwrapped to form a flat sheet. So the area of the sheet corresponds directly to the surface area. If the sheet is say 1 meter by 1 meter, then the area is 1*1 = 1 square meter. We can abbreviate "square meters" into "meter^2" or "m^2".

5 0
3 years ago
Read 2 more answers
Use the given transformation x=4u, y=3v to evaluate the integral. ∬r4x2 da, where r is the region bounded by the ellipse x216 y2
exis [7]

The Jacobian for this transformation is

J = \begin{bmatrix} x_u & x_v \\ y_u & y_v \end{bmatrix} = \begin{bmatrix} 4 & 0 \\ 0 & 3 \end{bmatrix}

with determinant |J| = 12, hence the area element becomes

dA = dx\,dy = 12 \, du\,dv

Then the integral becomes

\displaystyle \iint_{R'} 4x^2 \, dA = 768 \iint_R u^2 \, du \, dv

where R' is the unit circle,

\dfrac{x^2}{16} + \dfrac{y^2}9 = \dfrac{(4u^2)}{16} + \dfrac{(3v)^2}9 = u^2 + v^2 = 1

so that

\displaystyle 768 \iint_R u^2 \, du \, dv = 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2 \, du \, dv

Now you could evaluate the integral as-is, but it's really much easier to do if we convert to polar coordinates.

\begin{cases} u = r\cos(\theta) \\ v = r\sin(\theta) \\ u^2+v^2 = r^2\\ du\,dv = r\,dr\,d\theta\end{cases}

Then

\displaystyle 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2\,du\,dv = 768 \int_0^{2\pi} \int_0^1 (r\cos(\theta))^2 r\,dr\,d\theta \\\\ ~~~~~~~~~~~~ = 768 \left(\int_0^{2\pi} \cos^2(\theta)\,d\theta\right) \left(\int_0^1 r^3\,dr\right) = \boxed{192\pi}

3 0
2 years ago
-4x/7&gt;10 choose the solution set.
wolverine [178]

Answer:

I think it is c if not try to serch the answer up

3 0
3 years ago
Can someone help me with this? I'm confused
lakkis [162]

Answer:

The Answer is B

Step-by-step explanation

7 0
3 years ago
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