Question

A right pyramid with a square base has a base edge length of 12 meters and slant height of 6 meters.

Answer 1

Answer:apothem is 6

Hypotenuse of triangle is slant height

Height is 6

Volume of pyramid is 288

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

Square base of the base edge = 12 meters and slant height = 6√2 meters

Apothem of the right pyramid will be = AC

1). Now AC = $\sqrt{AB^{2}-BC^{2}}$

AC = $\sqrt{(6\sqrt{2})^{2}-(6)^{2}}$

     = $\sqrt{72-36}=\sqrt{36}$

     = 6

Now Apothem = 6 meters

2). Hypotenuse of Δ ABC = AB = 6√2 meters

3). Height AC = 6 meters

4). Volume of the pyramid = $\frac{1}{3}(\text{Area of the base})(\text{Apothem})$

Volume = $\frac{1}{3}(12)^{2}(6)$

             = 2×144

             = 288 meter²