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rjkz [21]
3 years ago
13

F(x)=9x+5, find f^-1(x).

Mathematics
1 answer:
lidiya [134]3 years ago
4 0

Answer:

interchange the role of x and y

x=9y+5

x-5=9y

<u>x-5</u><u> </u>=y

9

so,f^-1(x)= <u>x-5</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>9

hope it helps.

<h3>stay safe healthy and happy.</h3>
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Rafael has a bag of marbles, there are 5 green marbles, 6 red marbles, and 4
yulyashka [42]

The probability of getting red marble from the consider withdrawal of a marble is 0.107 approximately.

<h3>How to calculate the probability of an event?</h3>

Suppose that there are finite elementary events in the sample space of the considered experiment, and all are equally likely.

Then, suppose we want to find the probability of an event E.

Then, its probability is given as

P(E) = \dfrac{\text{Number of favorable cases}}{\text{Number of total cases}} = \dfrac{n(E)}{n(S)}

where favorable cases are those elementary events who belong to E, and total cases are the size of the sample space.

Given that:

The bag contains:

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Since he draws one marbel, thus, only one colored marble would come out.

Let we suppose we've to find P(red marble coming out).

Then, if we take:

E = event of Rafael drawing a red marble,

then E can be done in 6 ways as there are 6 red marbles to choose from.

Also, withdrawal of 1 marble (of any color) can be done in (5+6+45 = 56) 56 ways.

Thus, we get:

P(E) = P(\text{Choosing a red marble}) = \dfrac{6}{56} = \dfrac{3}{28} \approx 0.107

Thus, the probability of getting red marble from the consider withdrawal of a marble is 0.107 approximately.

Learn more about probability here:

brainly.com/question/1210781

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