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Darya [45]
3 years ago
5

CAN SOME ONE HELP ASAP WILL GIVE BRAINLIEST HURRRY PLZ

Mathematics
2 answers:
gulaghasi [49]3 years ago
5 0
1) x= Sally
x+5= Joe

In 15 years means to add 15 to Joe's age and that equals three times Sally's age (x).

(x+5) +15= 3x
x + 20=3x
20=2x
10= x

2) length= 2w+3
w= width

Perimeter= 2l + 2w
48= 2(2w+3) + 2w
48= 4w + 6 + 2w
48= 6w + 6
42= 6w
7=w

3) x= 1st integer
x+2= 2nd integer
x+4= 3rd integer

Since the integers are even, there has to be a difference of two between each one. 
5x= 3(x+2) +14
5x= 3x +6 +14
2x= 20
x=10

x+4= third consecutive integer = 10 + 4= 14

ANSWER: 1) 10 (second choice); 2) 7 (second choice); 3) 14 (third choice)

Hope this helps!  :)
vodomira [7]3 years ago
3 0
Number 1: 10

2: 7
3: 14n
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Convert 674 cm into m
Lyrx [107]

Answer is below. Look at my explanation to understand my answer.

To convert centimetres into meters, you'll divide how many centimetres by 100.

With that being said...

674 ÷ 100 = 6.74

Hence, 6.74 is your answer.

Let me know of any questions or concerns.

7 0
3 years ago
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Basile [38]
I believe the correct answer is 2.
5 0
3 years ago
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Please could I have some help :)
nirvana33 [79]

Answer:

a) x = 128 degrees

b) Angle APD is the arc angle, which is equal to the central angle x subtended by the arc.  Therefore angle APD = 128 degrees (and not 116 degrees)

Step-by-step explanation:

Given:

attached diagram

ABC is a straight line

Solution:

a) Find x

ABC is a straight line

angle ABD = supplement of CBD = 180-CBD = 180-116 = 64 degrees.

x is the central angle of the arc APD

so angle ABD is the inscribed angle which equals half of the arc angle =>

angle ABD = x/2 = 64 degrees

Solve for x

x/2 = 64

x = 2*64

x = 128 degrees

b.

Angle APD is the arc angle, which is equal to the central angle x subtended by the arc.  Therefore angle APD = 128 degrees (and not 116 degrees)

5 0
3 years ago
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Given the point and the slope, write the function in point-slope form:<br> (2, -5); m = 2/3
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Y=2/3x+(-5)
hope this helps
3 0
2 years ago
Compute <br><br> I need help
nataly862011 [7]

(\sqrt{3}-\sqrt{6}+\sqrt{12}-\sqrt{24})\times \frac{\sqrt{6}}{2} \\ (\sqrt{3}-\sqrt{6}+2\sqrt{3}-\sqrt{24})\times \frac{\sqrt{6}}{2} \\ (\sqrt{3}-\sqrt{6}+2\sqrt{3}-2\sqrt{6})\times \frac{\sqrt{6}}{2} \\ ((\sqrt{3}+2\sqrt{3})+(-\sqrt{6}-2\sqrt{6}))\times \frac{\sqrt{6}}{2} \\ (3\sqrt{3}-3\sqrt{6})\times \frac{\sqrt{6}}{2} \\ \frac{(3\sqrt{3}-3\sqrt{6})\sqrt{6}}{2} \\ \frac{3(\sqrt{3}-\sqrt{6})\sqrt{6}}{2}

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