Step-by-step explanation:
According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:
![\displaystyle Phase\:[Horisontal]\:Shift → \frac{0}{4} = 0 \\ Period → \frac{2}{4}π = \frac{π}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7B0%7D%7B4%7D%20%3D%200%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7B4%7D%CF%80%20%3D%20%5Cfrac%7B%CF%80%7D%7B2%7D)
Therefore we have our answer.
Extended Information on the trigonometric function
![\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Vertical%5C%3AShift%20%E2%86%92%20D%20%5C%5C%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7BC%7D%7BB%7D%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7BB%7D%CF%80%20%5C%5C%20Amplitude%20%E2%86%92%20%7CA%7C)
NOTE: Sometimes, your <em>vertical shift</em> might tell you to shift your graph below or above the <em>midline</em> where the amplitude is. Moreover, ALL <em>tangent</em>,<em> </em><em>secant</em>, <em>cosecant</em>, and <em>cotangent</em> functions have NO AMPLITUDE.
I am joyous to assist you anytime.
Hey there!
Since you probably have better things to do, your answer would be A: π(3)²
To back up my answer, the formula to find the area of a circle is π · R² where R = Radius. In that formula then, you just plug everything in. Since the radius is 3, you would put 3 into the "( )". Finally, just plug the rest of the equation in!
<em>I'm open to any question or comment!</em>
<em>God Bless!</em>
<em>-X8lue83rryX</em>
Answer:
-6×12×-1=72
Step-by-step explanation:
just note that abs(k)
when k<0
is -k
The dimensions would have to be 20 x 5 as the model holds the same amount for each side, and because 5 is larger than 4 its used as the models stand.
Hope it helps! :)
slope = change in y/ change in x
select two points on the line
(-4,4)
(0,1)
= (4-1)/(-4-0)
= -3/4
