Answer:
A and C are negative B and D are positive
Step-by-step explanation:
To solve this problem yo need to have the "x", the "y", and the radius. To find the radius since it is not given we use the formula.
sq rt(-3^2+1^2)
sq rt(9+1)
sq rt(10) would be the length of the radius in this case.
Then we use the sine cosine and tangent fractions
sin:y/r
cos:x/r
tan:y/x
With the values plugged in the equations are
SIN:1/sqrt(10) Since there can´t be a sq rt in hte denominator we change it to 1(sq rt(10))/10
COS:-3/sqrt(10) Since there can´t be a sq rt in the denominator we change it to -3(sq rt(10))/10
TAN:1/-3 This one can stay the same.
This would be the measures of SIN, COS, and TAN.
Answer:
(4, 3 )
Step-by-step explanation:
Given a system of equations graphically, then the solution is at the point of intersection of the 2 lines.
The lines intersect at (4, 3 ) ← solution
This equation is unsolvable.
x^2+8x+16=0
(x+4)^2+9=0
(x+4)^2= -9
anything to the power of whatever has to be greater than -1, it means it can be 0 or more but never a negative number. If it is a negative number, then it is false.
Answer:
Step-by-step explanation:
For 
the set of points that include all solutions are 
such that ; then we have 
.
What is important to stress here is that represents all of the solutions, while other points that we are given represent one solution (for example, point (2,-1) is just one solution)
