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kolezko [41]
4 years ago
11

Which values are solutions to the inequality below? Check all that apply. >4

Mathematics
2 answers:
GrogVix [38]4 years ago
7 0
Sqrt x > 4...by squaring both sides, this eliminates the sqrt
x > 4^2
x > 16

so B and C work....17 and 19
kirza4 [7]4 years ago
3 0
B and C because sqrt of 16=4 so sqrt of anything larger than 16 is greater than 4
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<u>Answer:</u>

The ratio of the complement of x to the supplement of x is 2:5. The value of x is 30

<u>Solution:</u>

It is given that x represents the measurement of an acute angle in degrees.  It is also given that the ratio of the complement of x to the supplement of x is 2:5.  

Since it is given that x is an acute angle it means that it has to be less than 90.

Complement of an angle = 90 - x

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In this case it is given that the ratio of the complement of x to the supplement of x is 2:5

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\begin{array}{l}{\frac{90-x}{180-x}=\frac{2}{5}} \\\\ {(90-x) \times 5=(180-x) \times 2} \\\\ {450-5 x=360-x) \times 2} \\\\ {450-560=5 x-2 x} \\\\ {90=3 x} \\\\ {x=\frac{90}{3}=30}\end{array}

Therefore the value of x is 30.

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