Use PEMDAS, which stands for Parenthesis, Exponents, Multiply, Divide, Add, and Subtract.
First multiply, so 86 x 450 = 38700, and then divide 47 divided by 10, which is 4.7, and then add 4.7 plus 38700, which would give you 38704.7
Factor out the 4 in both equations
8a^2-20^2=(2^2 times a^2 times 2)-(2^2 times 5)
therefor it is also equal to
(2a)^2 times 2-(2^2 times 5)
we can force it into a difference of 2 perfect squares which is a^2-b^2=(a-b)(a+b)
(2a√2)^2-(2√5)^2=((2a√2)-(2√5))((2a√2)+(2√5))
Answer:
a) 8.13
b) 4.10
Step-by-step explanation:
Given the rate of reaction R'(t) = 2/t+1 + 1/√t+1
In order to get the total reaction R(t) to the drugs at this times, we need to first integrate the given function to get R(t)
On integrating R'(t)
∫ (2/t+1 + 1/√t+1)dt
In integration, k∫f'(x)/f(x) dx = 1/k ln(fx)+C where k is any constant.
∫ (2/t+1 + 1/√t+1)dt
= ∫ (2/t+1)dt+ ∫ (1/√t+1)dt
= 2∫ 1/t+1 dt +∫1/+(t+1)^1/2 dt
= 2ln(t+1) + 2(t+1)^1/2 + C
= 2ln(t+1) + 2√(t+1) + C
a) For total reactions from t = 1 to t = 12
When t = 1
R(1) = 2ln2 + 2√2
≈ 4.21
When t = 12
R(12) = 2ln13 + 2√13
≈ 12.34
R(12) - R(1) ≈ 12.34-4.21
≈ 8.13
Total reactions to the drugs over the period from t = 1 to t= 12 is approx 8.13.
b) For total reactions from t = 12 to t = 24
When t = 12
R(12) = 2ln13 + 2√13
≈ 12.34
When t = 24
R(24) = 2ln25 + 2√25
≈ 16.44
R(12) - R(1) ≈ 16.44-12.34
≈ 4.10
Total reactions to the drugs over the period from t = 12 to t= 24 is approx 4.10
Answer:
Answer:
2x • (x2 - 2xy + 5x - 10y)
Step-by-step explanation:
Step 1 :
Equation at the end of step 1 :
(((2•(x3))+(10•(x2)))-(22x2•y))-20xy
Step 2 :
Equation at the end of step 2 :
(((2 • (x3)) + (2•5x2)) - 22x2y) - 20xy
Step 3 :
Equation at the end of step 3 :
((2x3 + (2•5x2)) - 22x2y) - 20xy
Step 4 :
Step 5 :
Pulling out like terms :
5.1 Pull out like factors :
2x3 - 4x2y + 10x2 - 20xy =
2x • (x2 - 2xy + 5x - 10y)
Final result :
2x • (x2 - 2xy + 5x - 10y)
Step-by-step explanation: