PLEASE help me please i really need the help

Mathematics

1 answer:

jenyasd209 [6]3 years ago

7 0

Answer: number two

Step-by-step explanation: i really hope this helps

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Over the course of a week, an environmental activist randomly stopped 1,200 people on the street and asked whether they were wil

sdas [7]

Sample Size = n = 1200
Number of people who are willing to pay higher = x = 708

Proportion of people who are willing to pay higher = p = $\frac{708}{1200}= \frac{59}{100}=0.59$

Confidence Level = 99%
Z Value = z = 2.58

The confidence interval about a population proportion can be calculated as:

$(p-z \sqrt{ \frac{p(1-p)}{n} }, p+z \sqrt{ \frac{p(1-p)}{n} })$

Using the values, we get:

$(0.59-2.58 \sqrt{ \frac{0.59(0.41)}{1200} } ,0.59+2.58 \sqrt{ \frac{0.59(0.41)}{1200} }) \\ \\ 
(0.553,0.627)$

Thus, at 99% confidence level, the estimated proportion of people willing to pay higher prices for gas in order to protect the environment lies between 0.553 and 0.627.

6 0

3 years ago

Read 2 more answers

Does someone understand this question and can help

KIM [24]

Answer:

It A or the first one

Step-by-step explanation:

4 0

4 years ago

the number of a certain company’s video stores can be approximated by the linear equation y=-264x+4682, where x is the number of

kogti [31]

This problem is incomplete, but I think I know the probable question. Normally, you should have been given the target number of the company's video stores, so that you can replace the value of y and solve for x. Once you solve for x, you add this to year 1990 then you can solve for the year at which you can reach your target value. Suppose y = 3500 stores.

3500 = -264x + 4682
3500 - 4682 = -264x
-1182 = -264x
x = 4.48 years

Technically, that is equal to 4 years. Hence, the year would be 1990+4 = 1994.

8 0

4 years ago

The distribution of blood cholesterol level in the

qaws [65]

Answer: A. Mean of sampling means $=\mu=168\ Mg/dl$