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3 years ago

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a large balloon in the shape of a sphere is being filled with helium. The balloon has a radius of 1 foot. Helium costs $0.80 per

cubic foot. What is the cost of filling the balloon with helium?

1 answer:

zhenek [66]3 years ago

4 0

Answer:

$3.35

Step-by-step explanation:

volume of balloon in the shape of sphere= 4/3 * pi * r^3 = 4.189 cubic foot

cost of 1 cubic foot of helium = 0.8

cost of 1 * 4.189 cubic foot of helium = 0.8 * 4.189 = 3.35

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6, 12, 8, 14, 10, 16<br>What pattern do you notice here

spin [16.1K]

6,12,8,10,16

6+6=12-4=8+6=14-4=10+6=6
The pattern I noticed is it adds 6 and then it minus 4.

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3 years ago

Read 2 more answers

A bakery the price of the cake is nine dollars more than the price of a pie. One day the bakery sold 8 cakes and 14 pies for a t

gavmur [86]

Answer:

The price of the cake is $24 and the price of the Pie is $15

Step-by-step explanation:

Given

<em>Represent price of Cake with C and Price of Pie with P</em>

$C = 9 + P$

Cakes sold = 8

Pies sold = 14

$Total = \$402$

Required

Determine C and P

To represent the cakes and pies sold, we have the following expression

$8C + 14P = 402$

Substitute 9 + P for C

$8(9+P) + 14P = 402$

Open the bracket

$72 + 8P + 14P = 402$

Collect Like Terms

$8P + 14P = 402 - 72$

$22P= 330$

Divide both sides by 22

$P = \frac{330}{22}$

$P = 15$

Recall that

$C = 9 + P$

$C = 9 + 15$

$C = 24$

<em>Hence, the price of the cake is $24 and the price of the Pie is $15</em>

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3 years ago

Monitors manufactured by TSI Electronics have life spans that have a normal distribution with a variance of 4,000,000 and a mean

In-s [12.5K]

Using the normal distribution, it is found that there is a 0.2776 = 27.76% probability that the life span of the monitor will be more than 20,179 hours.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 19000, \sigma = \sqrt{4000000} = 2000$

The probability that the life span of the monitor will be more than 20,179 hours is <u>one subtracted by the p-value of Z when X = 20179</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{20179 - 19000}{2000}$

Z = 0.59.

Z = 0.59 has a p-value of 0.7224.

1 - 0.7224 = 0.2776.

0.2776 = 27.76% probability that the life span of the monitor will be more than 20,179 hours.

More can be learned about the normal distribution at brainly.com/question/24663213

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2 years ago

How many hours of sleep do most people need to function properly?

Juliette [100K]

Answer:

7

Step-by-step explanation:

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3 years ago

(Calculus help, 25 points, will give brainliest) Find the sum of the sigma notation below.

Andreyy89

$\displaystyle\sum_{i=3}^{10}(2i-9)=2\sum_{i=3}^{10}i-9\sum_{i=3}^{10}1$

Recall that

$\displaystyle\sum_{i=1}^n1=n$

$\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2$

Your sums start at $i=3$ , so in order to apply these formulas directly, you need to compensate for the missing first two terms:

$\displaystyle\sum_{i=3}^{10}1=\sum_{i=1}^{10}1-(1+1)=10-2=8$

$\displaystyle\sum_{i=3}^{10}i=\sum_{i=1}^{10}i-(1+2)=\frac{10\cdot11}2-3=52$

$\implies\displaystyle\sum_{i=3}^{10}(2i-9)=2\cdot52-9\cdot8=\boxed{32}$

4 0

2 years ago