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Paha777 [63]
3 years ago
6

Here's a graph of a linear function. Write the equation that describes that function. (If blurry zoom in.)

Mathematics
1 answer:
Lerok [7]3 years ago
4 0

Answer:

y=\frac{1}{4}x+3

Step-by-step explanation:

we know that

The linear equation in slope intercept form is equal to

y=mx+b

where

m is the slope

b is the y-intercept

Find the slope

Take two points from the graph

(0,3) and (4,4)

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute

m=\frac{4-3}{4-0}

m=\frac{1}{4}

The y-intercept is the point (0,3)

so

b=3

substitute

y=\frac{1}{4}x+3

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astra-53 [7]

Answer:

f(2+h)=-(h+2/3)^2+1/4

f(x+h)=-(x+h-1/2)^2+1/4

Step-by-step explanation:

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=-(h+2/3)^2+1/4

2. Let (x+h)=a, then rewrite the equation into f(a)=a-a^2.

a-a^2=-(a^2-a)=-[(a-1/2)^2-1/4]=-(a-1/2)^2+1/4.

Insert a=x+h, f(x+h)=-(x+h-1/2)^2+1/4

7 0
3 years ago
7 qt =___fl oz how many fl oz
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HOW MANY 7 DIGIT TELEPHONE NUMBERS ARE POSSIBLE IF THE FIRST DIGIT CANNOT BE ZERO AND:
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Using the Fundamental Counting Theorem, the number of possible telephone numbers is given by:

a) 900,000.

b) 78,125.

c) 10,000.

<h3>What is the Fundamental Counting Theorem?</h3>

It is a theorem that states that if there are n things, each with n_1, n_2, \cdots, n_n ways to be done, each thing independent of the other, the number of ways they can be done is:

N = n_1 \times n_2 \times \cdots \times n_n

For item a, a multiple of 100 means that the last two digits are 00, hence the parameters are:

n_1 = 9, n_2 = n_3 = n_4 = n_5 = 10, n_6 = n_7 = 1

Hence the number is:

N = 9 x 10^5 = 900,000.

For item b, odd digits are 1, 3, 5, 7 and 9, hence the parameters are:

n_1 = n_2 = n_3 = n_4 = n_5 = n_6 = n_7 = 5

Hence the number is:

N = 5^7 = 78,125.

For item c, if the first 3 digits are 277, the parameters are:

n_1 = n_2 = n_3 = 1, n_4 = n_5 = n_6 = n_7 = 10

Hence the number is:

N = 10^4 = 10,000.

More can be learned about the Fundamental Counting Theorem at brainly.com/question/24314866

#SPJ1

3 0
2 years ago
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