Key word: sum
twice a number = 2n
Sum of that and 15 = 2n + 15
is = equals
Answer: 2n + 15 = 9
Answer:
f(2+h)=-(h+2/3)^2+1/4
f(x+h)=-(x+h-1/2)^2+1/4
Step-by-step explanation:
1. f(2+h)=(2+h)-(2+h)^2=2+h-4-4h-h^2=-h^2-3h-2=-(h^2+3h+2)
=-(h+2/3)^2+1/4
2. Let (x+h)=a, then rewrite the equation into f(a)=a-a^2.
a-a^2=-(a^2-a)=-[(a-1/2)^2-1/4]=-(a-1/2)^2+1/4.
Insert a=x+h, f(x+h)=-(x+h-1/2)^2+1/4
It is the first one, (x,y) to (-x,y) because it is going across the y axis from the positive side, so y stays the same but x becomes negative
Using the Fundamental Counting Theorem, the number of possible telephone numbers is given by:
a) 900,000.
b) 78,125.
c) 10,000.
<h3>What is the Fundamental Counting Theorem?</h3>
It is a theorem that states that if there are n things, each with
ways to be done, each thing independent of the other, the number of ways they can be done is:

For item a, a multiple of 100 means that the last two digits are 00, hence the parameters are:

Hence the number is:
N = 9 x 10^5 = 900,000.
For item b, odd digits are 1, 3, 5, 7 and 9, hence the parameters are:

Hence the number is:
N = 5^7 = 78,125.
For item c, if the first 3 digits are 277, the parameters are:

Hence the number is:
N = 10^4 = 10,000.
More can be learned about the Fundamental Counting Theorem at brainly.com/question/24314866
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