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3 years ago

7

Joey's sock drawer is unorganized and contains 7 black dress socks, 3 black ankle socks, 2 brown dress socks, and 4 brown ankle

socks. What is the
probability that Joey will blindly reach into his sock drawer and pull out a sock that is brown or a dress sock

1 answer:

Flauer [41]3 years ago

8 0

Answer:

%37.5

Step-by-step explanation:

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Dan's ice cream comes on cartons of two sizes. the large carton holds 4 1/2 pounds. the small carton holds 1 3/4 pounds less. ho

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2 3/4
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2 years ago

Because the three sides are congruent, what foes that make each angle measure according to the equilateral triangle theorem.

m_a_m_a [10]

Answer : 60 degrees
Explanation: All triangles's angles add up to 180. Since all angles are equal, you can divide 180 by 3. 180/3 is 60

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3 years ago

Read 2 more answers

Can someone explain how to do these questions or show me how?

AleksAgata [21]

Check the picture below.

bear in mind that since we have a radical in the denominator, we'd rationalize the denominator to take it off the denominator.

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3 years ago

Suppose a triangle has two sides of length 33 amd 37, and that the angle between these two sides is 120°. What is the length of

jeka57 [31]

Answer:

c = 60.65 cm

Step-by-step explanation:

Given that,

The two sides of a triangle are 33 cm and 37 cm.

The angle between these two sides is 120°.

We need to find the length of the third side of the triangle. Let c is the third side. Using cosine rule,

$c^2=a^2+b^2-2ab\cos C$

a = 33 cm, b = 37 cm and C is 120°

So,

$c^2=(33)^2+(37)^2-2\times 33\times 37\cos (120)\\\\c=60.65\ cm$

So, the length of the third side of the triangle is 60.65 cm.

7 0

2 years ago

What is lim x→3 x^2 - x - 6/ x - 3

Kisachek [45]

<h3>Answer: D) 5</h3>

=======================================================

Explanation:

If we plugged x = 3 into the expression, then we'd get x-3 = 3-3 = 0 in the denominator. That's not allowed. But we can simplify first

x^2-x-6 factors to (x-3)(x+2). The key here is that (x-3) is a factor. It cancels with the x-3 in the denominator

So, $\frac{x^2-x-6}{x-3} = \frac{(x-3)(x+2)}{x-3} = x+2$

Allowing us to say,

$\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}\frac{(x-3)(x+2)}{x-3}\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}(x+2)\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 3+2\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 5\\\\\\$

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3 years ago