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3 years ago

Solve this equation using the least common denominator ?

Mathematics

1 answer:

Likurg_2 [28]3 years ago

6 0

The answer would be
A. 3/4

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If Randy sells 8 times as many vacuum cleaners as Janice, and Janice sells 690 vacuum cleaners per year, on average, how many do

drek231 [11]

Randy sells, in average, 460 vacuum cleaners per month.

<h3>How many vacuum cleaners does Randy sell each month?.</h3>

First, we know that Janice sells 690 units per year.

There are 12 months in a year, so the amount that she sells, in average, per month is:

J = 690/12 = 57.5

This means that Janice sells, in average, 57.5 units per month. And Randy sells 8 times as many, then we can solve the product:

R = 8*57.5 = 460

This means that Randy sells 460 units per month.

If you want to learn more about products:

brainly.com/question/10873737

#SPJ2

7 0

1 year ago

Triangle HIJ has vertices H(1, 7) , I(−4, −2) , and J(−3, 5) . Write the coordinate notation for a translation of 3 units right

e-lub [12.9K]

Step-by-step explanation:

(x, y) -> (x+3, y+4)

that is what 3 units to the right (3 units into the outsource x direction) and 4 units up (4 units into the posits y directing) mean.

so, all points go through this translation

(1, 7) -> (4, 11)

(-4, -2) -> (-1, 2)

(-3, 5) -> (0, 9)

3 0

1 year ago

Of the 145 students who took a mathematics exam, 80 correctly answered the first question, 81 correctly answered the second ques

jasenka [17]

Answer: 64

Step-by-step explanation:

the Kids that answered correct in any of questions 1 and 2 got at least one right so subtract the highest number which is 81 students by all the general amount of them, 145 that’s 64.

3 0

2 years ago

Evaluate the line integral, where c is the given curve. c y3 ds,

postnew [5]

Parameterizing $\mathcal C$ by

$\mathbf r(t)=(t^3,t)$

with $0\le t\le2$ , we have

$\mathrm ds=\|\mathbf r'(t)\|\,\mathrm dt=\sqrt{(3t^2)^2+1^2}\,\mathrm dt=\sqrt{9t^4+1}\,\mathrm dt$

So

$\displaystyle\int_{\mathcal C}y^3\,\mathrm ds=\int_{t=0}^{t=2}t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_0^236t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_{u=1}^{u=145}\sqrt u\,\mathrm du$
$=\dfrac{145^{3/2}-1}{54}$

5 0

2 years ago

HELPPPPPPPPPP!!!!!!!!!!

juin [17]

Answer:

The last one

Step-by-step explanation:

measure angle 2 and 6 to see if congruent

4 0

2 years ago