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kotykmax [81]
2 years ago
7

The quadratic function g(x) = ax^2 + bx + c has the complex roots (-5+9i) and (-5-9i). (you may assume that a = -1) what is the

value of b and c?
Mathematics
1 answer:
gavmur [86]2 years ago
4 0

Answer:

  • b = -10, c = -106

Step-by-step explanation:

<h3>Given</h3>

<u>Quadratic function </u>

  • g(x) = ax^2 + bx + c

with the roots:

  • (-5+9i) and (-5-9i)
<h3>To find </h3>
  • b and c if a = -1
<h3>Solution</h3>

<u>As we know the sum of the roots is -b/a and the product of the roots is c/a. Substituting values and solving for b and c:</u>

  • (-5 + 9i) + (-5 - 9i) = -b/-1
  • -10 = b
  • b = -10

And

  • (-5 + 9i)(-5 - 9i) = c/-1
  • (-5)² - (9i)² = -c
  • 25 - 81(-1) = -c
  • - c = 25 + 81
  • - c = 106
  • c = -106

g(x) = -x² -10x - 106

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Answer:

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Step-by-step explanation:

The sum you are trying to understand is this.

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n}

Remember that in general when you have a geometric series  

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Therefore here we have

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{3*5} \big)^n = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n        and   \big|\frac{-1}{15} \big| = \frac{1}{15} < 1

Therefore we can use the formula and

\sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n =  \frac{2}{1-(-1/15)} = \frac{2}{1+1/15} = 30/16  = 15/8

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<h3>What is a triangle?</h3>

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The sum of all the angles of a triangle is always equal to 180°. An isosceles triangle has two sides out of three equal.

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