This is a quadratic formula with a general form of a²x + bx + c = 0. For quadratic equations, we can solve for its two roots using the quadratic formula shown in the attached picture.
a = -3
b = -4
c = -4
x = [-(-4) + √(-4)² - 4(-3)(-4)]/2(-3) =
<em>2 + √-32/2</em>x = [-(-4) - √(-4)² - 4(-3)(-4)]/2(-3) =
<em> 2 - √-32/2</em>
Answer:
x=5
Step-by-step explanation:
(8x-8)3/2=64
(24x-8)/2=64 -You are distributing the three
12x-4=64 -You divide the whole thing by two
12x=60 -You subtract the four from both sides
x=5 - You divided the twelve from both sides
Hope this helps!
Answer:
C=10
Step-by-step explanation:
To solve this problem, first, you have to isolate it on one side of the equation. Remember, isolate c on one side of the equation.
3/2c+23-23=38-23 (subtract 23 from both sides.)
38-23 (solve.)
38-23=15
3/2c=15
2*3/2c=15*2 (multiply 2 from both sides.)
15*2 (solve.)
15*2=30
3c=30
3c/3=30/3 (divide by 3 from both sides.)
30/3 (solve.)
30/3=10
c=10
Answer: othingat all
Step-by-step explanation:
Answer:
Step-by-step explanation:
First you would see how many times 3 would go into 22 and it would be 7 with a remainder of 1. Then you would do 7 times 3 which is 21. And 22 minus 21 is 1. Then your answer would be 7 with a remainder of 1. If you don't want a remainder, and you want a decimal then you would add a decimal point after the 22 and then add a 0. You would bring down the zero and then the remainder of one would be 10 then you would see how much 3 goes into 10, and it only goes 3 times. Your answer would be 7.3 with a remainder of 1, If you keep going you will see it becomes a repeating decimal. *Hope it helped*
