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faust18 [17]
3 years ago
9

Solve for a. 2z=4a/m +3

Mathematics
1 answer:
Finger [1]3 years ago
4 0

Answer:

<h3>                a = (2mz - 3m)/4</h3>

Step-by-step explanation:

2z = 4a/m +3

 -3        -3

2z - 3 = 4a/m

 ×m        ×m

(2z -3)m = 4a

     ÷4      ÷4

[(2z -3)m]/4 = a

a = (2mz - 3m)/4

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Step-by-step explanation:

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3 years ago
PLEASE HELP!!!!<br><br><br> Thanks, Anyone who answers I appreciate it very much!!
Ivan

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Linear Decreasing

Step-by-step explanation:

Exponential graphs are curved, but this line is straight, so it's linear. It's decreasing since the graph moves from left to right, and as you can see, the line starts from the left tall but gradually goes lower as it goes towards the right.

6 0
2 years ago
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Joe began to increase the speed of his car at 2:00 P.M. Since that time,the speed of Joes car has been steadily increasing by 1
Olegator [25]

Answer:

7 mins

Step-by-step explanation:

Current speed of Joes Car = 65.5 mph

We have to find the time interval for which the car exceeded the speed limit of 55 mph.

While, we are given that the speed of the car was constantly increasing, hence the speed over all increased from the limit of 55 mph = 65.50-55.00 = 10.50 mph

We are also given that Joes car was increasing speed at a constant rate of 1.50 mph for every passing minute. Hence

1.50 mph is increased in 1 minute

1 mph will be increase in \frac{1}{1.5} minutes

Hence

10.50 mph will be increased in \frac{1}{1.5} \times 10.50 minutes

= \frac{10.5}{1.5}

=7

Hence joes car was exceeding the limit of 55 mph for 7 minutes.

8 0
3 years ago
What is the answer to this problom
Liula [17]
The answer would be 405 because
    
         405                                
      _____
    6|2430                     sorry for long example.
       24
      ___
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7 0
3 years ago
If a=2, b=3 and c=4 then find the numerical value of a2+2abc+b2+c2<br>​
qaws [65]

a=2 b=3 and c=4. then,

<em>a2+2abc+b2+c2</em>

<em>a2+2abc+b2+c2</em><em>=</em><em> </em><em>2</em><em>^</em><em>2</em><em>+</em><em>2</em><em>×</em><em>2</em><em>×</em><em>3</em><em>×</em><em>4</em><em>+</em><em>3</em><em>^</em><em>2</em><em>+</em><em>4</em><em>^</em><em>2</em>

<em>(</em><em>replace</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>a</em><em>,</em><em> </em><em>b</em><em>,</em><em> </em><em>c</em><em> </em><em>by</em><em>2</em><em>,</em><em>3</em><em>,</em><em>4</em><em> </em><em>respectively</em><em> </em><em>tgen</em><em> </em><em>solve</em><em>)</em>

<em>=</em><em> </em><em>4</em><em>+</em><em>4</em><em>8</em><em>+</em><em>9</em><em>+</em><em>1</em><em>6</em>

<em>=</em><em> </em><em>7</em><em>7</em><em>…</em><em>…</em><em>…</em><em>…</em><em>…</em><em>…</em>

<em> </em><em>Therefore</em><em>,</em><em> </em><em>7</em><em>7</em><em> </em><em>is</em><em> </em><em>correct</em><em> </em><em>answer</em><em>.</em>

7 0
3 years ago
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