A square tile has a side Length of 16cm. What is the area of the tile ?

The hockey team won 63 out of the 84 games it played this year.what percent of the games did the team win

Deffense [45]

63 is 75% of 84.
Percent of a Total

3 0

3 years ago

The contrapositive of p q is:

Kay [80]

Some symbols are missing. I'm assuming you meant to put in a horseshoe symbol like so $p \supset q$

If so, then the contrapositive of that would be $\sim q \supset \ \sim p$ which is the final answer.

The tilde sign $\sim$ means "not" so writing $\sim q$ means "not q" which is the complete opposite of q.

6 0

3 years ago

A Packaging Company produces boxes out of cardboard and has a specified weight of 16 oz. A random sample of 36 boxes yielded a s

user100 [1]

Answer:

The margin of error is of 0.73 oz.

The 99% confidence interval for the true mean weight of the boxes is between 14.57 oz and 16.03 oz. This means that we are 99% sure that the true mean weight of all boxed produced by the Packaging Company is between these two values, and that the specified weight is in this interval.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.005 = 0.995$ , so Z = 2.575.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 2.575\frac{1.7}{\sqrt{36}} = 0.73$

The margin of error is of 0.73 oz.

The lower end of the interval is the sample mean subtracted by M. So it is 15.3 - 0.73 = 14.57 oz.

The upper end of the interval is the sample mean added to M. So it is 15.3 + 0.73 = 16.03 oz.

The 99% confidence interval for the true mean weight of the boxes is between 14.57 oz and 16.03 oz. This means that we are 99% sure that the true mean weight of all boxed produced by the Packaging Company is between these two values, and that the specified weight is in this interval.

4 0

2 years ago

HELP PLZ <br> i need help with this math side i just need b,c,d a =4x+2y=16

tino4ka555 [31]

Answer:

Please check the explanatio.

Step-by-step explanation:

Solving Part b)

We know that the slope-intercept form of the equation line is

$y=mx+b$

where m is the slope and b is the y-intercept

Given the equation

$4x+2y=16$

Re-writing the equation in the slope-intercept form

$4x+2y=16$

$y=-2x+8$

Here, m=-2 and b=8

Thus, the equation in the slope-intercept form will be:

$y=-2x+8$

Solving Part c)

As you sold two pounds of cheddar cheese.

i.e. y=2

substituting y=2 in the slope-intercept form of the line equation

$y=-2x+8$

$2=-2x+8$

Subtract 8 from both sides

$-2x+8-8=2-8$

$-2x=-6$

Divide both sides by -2

$\frac{-2x}{-2}=\frac{-6}{-2}$

$x=3$

You sold 3 pounds of swiss cheese.

Solving Part d)

$y=-2x+8$

putting x=2.5 in the equation

$y=-2x+8$

$2=-2\left(2.5\right)+8$

$2=3$

The sides are not equal

<em>FALSE</em>

Thus, x=2.5 does not make any sense in the context of the problem.

6 0

2 years ago

Sally was the waitress at two tables. At the first table the bill came to $38.70 and the tip was 15%. At the second table the bi

rewona [7]

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hfill \stackrel{\textit{15\% of 38.70}}{\left( \cfrac{15}{100} \right)38.70}\implies \underline{5.805}~\hfill \stackrel{\textit{20\% of 33.45}}{\left( \cfrac{20}{100} \right)33.45}\implies \stackrel{\textit{larger}}{\underline{6.69}} \\\\\\ \stackrel{\textit{by how much?}}{6.69-5.805\implies 0.885}$

3 0

3 years ago