Suppose you have gone bowling with an excellent player who bowls a strike (i.e. when they hit all of the pins) 73% of the time. By the fourth frame, this person realizes that they can clinch first place in a local tournament by bowling 3 consecutive strikes. What is the likelihood of this happening
1 answer:
Answer:
The probability of bowling 3 consecutive strikes is 0.3890 .
Explanation:
On any given turn, this player has a 73% chance of bowling a strike. Hence:
Probability of bowling a strike = P(S) = 73% = 0.73
We need to find the probability of this player bowling 3 consecutive strikes . This is computed as follows:
Probability of bowling 3 consecutive strikes
= Probability of bowling first strike x Probability of bowling second strike x Probability of bowling third strike
= P(S) x P(S) x P(S)
= 0.73 x 0.73 x 0.73
= 0.3890
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For two parallel lines. their slope are equal
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