Answer:
a) Between 74 and 90
b) 81.86% of the scores are between 78 and 90
Step-by-step explanation:
a) According to the Empirical Rule, in a normal distribution, 95% of the data are within 2 standard deviations of the mean. Therefore, the range that 95% of the scores fall in is between 82-4(2)=74 and 82+4(2)=90.
b) The percent of scores that are between 78 and 90 is: normalcdf(lower,upper,μ,σ) = normalcdf(78,90,82,4) = 0.8185946784 ≈ 0.8186, or about 81.86% of the scores.
Steps:
Use the divisor and find x :
x - 1 = 0 **add 1
x= 1
Now we will use the 1 in dividing:
take the coefficients from in front of all terms
** make sure you include 0's for x^2 and x since you have to have all terms
set it up with a 1 in a box:
1| 1 0 0 1 **bring the first number down
____________
1 **multiply the boxed number by the first number and add it to the second number
1| 1 0 0 1
____+1_____ **repeat with the rest of the terms
1 1
1| 1 0 0 1
___+1_+1_+1
1 1 1 2
**when you're done, use the new numbers to write an equation starting with a term with a degree one less than the previous equation.
**since there is a remainder, rewrite it divided by the original divisor
final answer:
x^2 + x + 1 + (2/ x -1)
yes, they are all proportional
Let
n-------> the number of nickels
q------> the number of quarters
we know that
so
----> equation A
----> equation B
substitute equation B in equation A
![0.05n+0.25[3n]=1.60](https://tex.z-dn.net/?f=0.05n%2B0.25%5B3n%5D%3D1.60)
Find the value of q
therefore
<u>The answer part a) is</u>
the number of nickels are 
and the number of quarters are 
<u>the answer Part b) is</u>
The expressions that represents the number of quarters is
Hello!
We are given that each of the 5 alligators has 100 teeth. We can use the following equation to find the total number of teeth and, by extension, the total number of bite marks:
(100 teeth) × (5 alligators) = 500 teeth
We have now proven that the 5 alligators have a combined total of 500 teeth. Consequently, Sammy will have 500 bite marks.
I hope this helps!
