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3 years ago

7

Find the simplest pattern and insert the missing terms of the sequences. o, t, t, f, f, s, s, e, n, ...

2 answers:

Fed [463]3 years ago

8 0

O is one
T is two
T is three
F is four
F is five
S is six
S is seven
E is eight
N is nine
The next two terms
T for ten and e for eleven

ddd [48]3 years ago

3 0

Answer:

The letters are the first letter of their corresponding numbers (one, two, three = o, t, t). This means that the next terms will be t, e, t, t, f, f, s, s, e, n, t and so on.

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What is equivalent to 1/40

Nimfa-mama [501]

2/80 is equivalent
you can also just multiply the numerator and denominator to find out what else is equivalent.

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3 years ago

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Find the measure of angle A (please help!!!)

mel-nik [20]

Answer: 41 degrees

Step-by-step explanation:

so, we know that a triangle is 180 degrees. since we know that one angle is 80 degrees, we can subtract that from the equation. now, we are trying to find what X is so that we can find the angle. here is how i did it:

i rewrote it and removed the parentheses.

4x + 1 + 4x + 19 = 100

then, i collected like terms and calculated it.

8x + 20 = 100

then, i moved the constant to the right.

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7 0

3 years ago

What is the scale factor of triangle ABC to triangle XYZ?

Alex

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3 years ago

Whats the inequality of R-2<7

VashaNatasha [74]

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3 years ago

Help please<3 for all questions with solutions plz

antiseptic1488 [7]

Answer:

a) $h = -\frac{7}{4}$ , b) $h = f\,\circ\,g (-5) = \frac{3}{2}$ , c) $h = g\,\circ\,f (-2) = \frac{3}{8}$

Step-by-step explanation:

We proceed to solve each exercise below:

a) $f(-2) +3\cdot g(0)$

$h = \frac{2\cdot (-2)}{3\cdot (-2)+5}+3\cdot \left(\frac{3}{0+4} \right)$

$h = \frac{-4}{-6+5} +3\cdot \left(\frac{3}{4} \right)$

$h = -4+\frac{9}{4}$

$h = \frac{-16+9}{4}$

$h = -\frac{7}{4}$

b) $h = f\,\circ \,g (-5)$

$h = f\,\circ\,g (x) = \frac{\frac{6}{x+4} }{\frac{9}{x+4}+5 }$

$h = f\,\circ\,g (x)= \frac{\frac{6}{x+4} }{\frac{9+5\cdot (x+4)}{x+4} }$

$h = f\,\circ\,g (x) = \frac{6}{29+5\cdot x}$

$h = f\,\circ\,g (-5) = \frac{6}{29+5\cdot (-5)}$

$h = f\,\circ\,g (-5) = \frac{3}{2}$

c) $h = g\,\circ\,f(-2)$

$h = g\,\circ \, f (x) = \frac{3}{\frac{2\cdot x}{3\cdot x + 5} + 4 }$

$h = g\,\circ\,f (x) = \frac{3}{\frac{2\cdot x +4\cdot (3\cdot x +5)}{3\cdot x +5 } }$

$h = g\,\circ \,f (x) = \frac{3\cdot (3\cdot x +5)}{2\cdot x +12\cdot x +20}$

$h = g\,\circ\,f(x) = \frac{9\cdot x +15}{14\cdot x +20}$

$h = g\,\circ\,f(-2) = \frac{9\cdot (-2)+15}{14\cdot (-2)+20}$

$h = g\,\circ\,f (-2) = \frac{-3}{-8}$

$h = g\,\circ\,f (-2) = \frac{3}{8}$

6 0

3 years ago