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3 years ago

Find the simplest pattern and insert the missing terms of the sequences. o, t, t, f, f, s, s, e, n, ...

2 answers:

8 0

O is one
T is two
T is three
F is four
F is five
S is six
S is seven
E is eight
N is nine
The next two terms
T for ten and e for eleven

ddd [48]3 years ago

3 0

Answer:

The letters are the first letter of their corresponding numbers (one, two, three = o, t, t). This means that the next terms will be t, e, t, t, f, f, s, s, e, n, t and so on.

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Abby rode the Metro bus 4 miles farther than James rode. The sum of their distances traveled is 28 miles. How far did James ride

ohaa [14]

A. define the variables : a = abby's miles, j = james' miles

b. a = j + 4......j = a - 4

c. a + j = 28
a = j + 4

d. (j + 4) + j = 28
2j + 4 = 28
2j = 28 - 4
2j = 24
j = 24/2
j = 12

a = j + 4
a = 12 + 4
a = 16

e. check..
a + j = 28
16 + 12 = 28
28 = 28 (correct)

solution is : abby's miles (a) = 16
james' miles (j) = 12

8 0

2 years ago

The product of two and x plus the quotient of w and five

Nataly [62]

Answer:

2x+w/5

Step-by-step explanation:

(2*x)+(w/5)

2x +w/5

8 0

3 years ago

What is the solution for this set of equation (2r-3)-4=37

Alex777 [14]

Answer:

(2r-3)-4=37

or,(2r-3)=37+4

or,2r-3=41

or,2r=41+3

or,2r=44

or, r= 44/2

hence , r= 22

5 0

3 years ago

[20 pts] evaluate the logarithm log(6)1/36, show work pls!

Delvig [45]

Answer:

$\large\boxed{\log_6\dfrac{1}{36}=-2}$

Step-by-step explanation:

$\text{We know:}\\\\\log_ab=c\iff a^c=b\\\\\log_6\dfrac{1}{36}\qquad\text{use}\ a^{-1}=\dfrac{1}{a}\\\\=\log_636^{-1}=\log_6(6^2)^{-1}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\log_66^{(2)(-1)}=\log_66^{-2}\qquad\text{use}\log_ab^n=n\log_ab\\\\=-2\log_66\qquad\text{use}\ \log_aa=1\\\\=-2(1)=-2$

$\log_6\dfrac{1}{36}=-2\ \text{because}\ 6^{-2}=\dfrac{1}{6^2}=\dfrac{1}{36}$

8 0

3 years ago

I need help right now please

Hoochie [10]

8/1 + (x-1)/(x+4)
You need the same common denominator (bottom number) to be able to add together so multiply 8 by (x+4) to both bottom and top

8 (x+4)/(x+4) + (x-1)/(x+4)
Add
8 (x+4)+(x-1)/ (x+4)
Distribute the 8 to (x+4)
8x+32+x-1 / x+4
Simplify

9x+31/x+4
:)

8 0

2 years ago