Answer:
You can recognize that .25 is 1/4, so 0.625 is 1/4 of the way
from 0.6 to 0.7
1 ten
2 hundreds?
18 ones?
218
6.
![y^2\sqrt[8]{8}](https://tex.z-dn.net/?f=y%5E2%5Csqrt%5B8%5D%7B8%7D)
Step-by-step explanation:
![\sqrt[8]{8*y*y*y*y*y*y*y*y*y*y*y*y*y*y*y*y}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7B8%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%7D)
Since there are eight y's in two groups we can take them out which turns into
![y^2\sqrt[8]{8}](https://tex.z-dn.net/?f=y%5E2%5Csqrt%5B8%5D%7B8%7D)
:)
3.
9514 1404 393
Answer:
y = 7
Step-by-step explanation:
The slope is ...
m = (7 -7)/(0 -4) = 0
The y-intercept is the point (0, 7), so the slope-intercept equation is ...
y = mx +b
y = 0·x +7
Simplifying this puts it in standard form:
y = 7
Answer:
60 minutes for the larger hose to fill the swimming pool by itself
Step-by-step explanation:
It is given that,
Working together, it takes two different sized hoses 20 minutes to fill a small swimming pool.
takes 30 minutes for the larger hose to fill the swimming pool by itself
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
<u>To find LCM of 20 and 30</u>
LCM (20, 30) = 60
<u>To find the efficiency </u>
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
x = 60/30 =2
x + y = 60 /20 = 3
Therefore efficiency of y = (x + y) - x =3 - 2 = 1
so, time taken to fill the swimming pool by small hose = 60/1 = 60 minutes