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3 years ago

Evaluate 6 P 3. 720 240 540 120

Mathematics

1 answer:

skad [1K]3 years ago

6 0

Answer:120

Step-by-step explanation: i know i am a week late but ...

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Let g be the function given by g(x)=limh→0sin(x h)−sinxh. What is the instantaneous rate of change of g with respect to x at x=π

lorasvet [3.4K]

The instantaneous rate of change of g with respect to x at x = π/3 is 1/2.

<h3>How to determine the instantaneous rate of change of a given function</h3>

The instantaneous rate of change at a given value of $x$ can be found by concept of derivative, which is described below:

$g(x) = \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}$

Where $h$ is the difference rate.

In this question we must find an expression for the instantaneous rate of change of $g$ if $f(x) = \sin x$ and evaluate the resulting expression for $x = \frac{\pi}{3}$ . Then, we have the following procedure below:

$g(x) = \lim_{h \to 0} \frac{\sin (x+h)-\sin x}{h}$

$g(x) = \lim_{h \to 0} \frac{\sin x\cdot \cos h +\sin h\cdot \cos x -\sin x}{h}$

$g(x) = \lim_{h \to 0} \frac{\sin h}{h}\cdot \lim_{h \to 0} \cos x$

$g(x) = \cos x$

Now we evaluate $g(x)$ for $x = \frac{\pi}{3}$ :

$g\left(\frac{\pi}{3} \right) = \cos \frac{\pi}{3} = \frac{1}{2}$

The instantaneous rate of change of g with respect to x at x = π/3 is 1/2. $\blacksquare$

To learn more on rates of change, we kindly invite to check this verified question: brainly.com/question/11606037

4 0

2 years ago

A boat leaves a.M. Marina at 7 AM traveling at 3.4 knots bearing is N38°E the boat docks on an island at 2pm how far north of th

Jlenok [28]

Answer:

The distance between the docks & island is 44.07 km.

Step-by-step explanation:

Speed of the boat S = 3.4 knot = 6.3 $\frac{km}{hr}$

Time taken by bot to reach the island = 7 hr

We know that the distance is given by

Distance = Speed × Time

Put all the values in above equation we get

D = 6.3 × 7

D = 44.07 km

Therefore the distance between the docks & island is 44.07 km.

6 0

2 years ago

Pierre's company bought cement for $5.25 per bag . If they sold the cement for $7.35 per bag. What was the markup rate ?

qwelly [4]

2.15$ would be the mark up rate.

5 0

3 years ago

This is my first year doing edge and was wondering if the exams are super hard ?

Otrada [13]

It depends, because sometimes they are difficult and sometimes not ...

Have a good Saturday...

3 0

3 years ago

2/15 + 27/35 = what in reduced terms

solniwko [45]

2/15 + 27/35 = 14+81 /105 = 95/105 = 19/21

so, your answer is 19/21

8 0

3 years ago