Answer:
It will take the 20 years for the population to quadruple.
Step-by-step explanation:
Exponential population growth:
An exponential model for population growth has the following model:
In which P(0) is the initial population and r is the growth rate, as a decimal.
It grows with a doubling time of 10 years.
This means that 
. We use this to find r. So
![\sqrt[10]{(1+r)^10} = \sqrt[10]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B10%5D%7B%281%2Br%29%5E10%7D%20%3D%20%5Csqrt%5B10%5D%7B2%7D)
So
Determine how long it will take for the population to quadruple.
This is t for which P(t) = 4P(0). So
It will take the 20 years for the population to quadruple.
This is substitution, it's very simple once you get the hang of it!
okay, what you want to do is plug in the numbers you already have, to get the number you don't have(r).
First, you plug in the numbers.
1. P= $2000
A=$2543
t= 4(years)
r=?
2543=2000^r(4)
Secondly, you want to solve the equation.
Answer:
400 meters
Step-by-step explanation:
H(t) = −16t^2 + 75t + 25
g(t) = 5 + 5.2t
A)
At 2, h(t) = 111, g(t) = 15.4
At 3, h(t) = 106, g(t) = 20.6
At 4, h(t) = 69, g(t) = 25.8
At 5, h(t) = 0, g(t) = 31
The heights of both functions would have been the closest value to each other after 4 seconds, but before 5 seconds. This is when g(x) is near 30 (26-31), and the only interval that h(t) could be near 30 is between 4 and 5 seconds (as it is decreasing from 69-0).
B) The solution to the two functions is between 4 and 5 seconds, as that is when their height is the same for both g(t) and h(t). Actually the height is at 4.63 seconds, their heights are both
What this actually means is that this time and height is when the balls could collide; or they would have hit each other, given the same 3-dimensional (z-axis) coordinate in reality.
45.5 is your answer, you will have to multiple the height times the base ( 5 x 9.1 )
