Answer:
No, because it fails the vertical line test ⇒ B
Step-by-step explanation:
To check if the graph represents a function or not, use the vertical line test
<em>Vertical line test:</em> <em>Draw a vertical line to cuts the graph in different positions, </em>
- <em>if the line cuts the graph at just </em><em>one point in all positions</em><em>, then the graph </em><em>represents a function</em>
- <em>if the line cuts the graph at </em><em>more than one point</em><em> </em><em>in any position</em><em>, then the graph </em><em>does not represent a function </em>
In the given figure
→ Draw vertical line passes through points 2, 6, 7 to cuts the graph
∵ The vertical line at x = 2 cuts the graph at two points
∵ The vertical line at x = 6 cuts the graph at two points
∵ The vertical line at x = 7 cuts the graph at one point
→ That means the vertical line cuts the graph at more than 1 point
in some positions
∴ The graph does not represent a function because it fails the vertical
line test
Answer:
18.25
Step-by-step explanation:
Answer:
+5 Range; The range is now 25
Step-by-step explanation:
The original range would be calculated by subtracting 20 from 40, giving you 20 as the range. However, with the point 15 added, there would be a new lowest number, making the new range be 40-15, which is 25.
Answer:
7n-10
Step-by-step explanation:
=(5n-3) - (-2n) -7 [Bracket Opens]
=5n - 3 +2n -7 [- × - = +]
=7n - 10 [ addition]
Answer:
-1/2
Step-by-step explanation:
In a linear relationship, the rate of change of one variable with respect to the other is <em>constant</em>. When we talk about <em>change</em>, we're looking for a <em>difference</em> of values.
If we look at the first and second rows, the change in x is 1 - (-1) = 2, while the change in y is 9 - 10 = -1. Usually we refer to these changes as Δx and Δy (read like "delta-x" and "delta-y"), and the <em>rate of change </em>is the number we get by dividing one of these by the other.
The rate of change we're used to seeing, sometimes called the <em>slope</em>, is Δy/Δx. So, using the values we've already found:
