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Keith_Richards [23]
3 years ago
9

Solve and show how pls

Mathematics
1 answer:
irakobra [83]3 years ago
4 0

Answer:

16

Step-by-step explanation:

since -4 is being squared, we can write it out as -4 * -4, to get us the answer 16. this answer is positive because a negative times a negative will cancel out and = a positive.

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I need help on #12 please
Novosadov [1.4K]
So 10.38 gal at 2.289 oer gal but you want american mony so round 2.289 to two decimal places so 2.29 per gallon

2.29 times 10.38=23.7702 but you just cross out the '2' in the ten-thousanth's place because 1/50 of a cent is really small


it is not possible to pay 9/10 of a cent so they just want you to round it up to 1 cent or10/10 cent
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Construct a tangent to the circle at point B.<br><br> PLEASE HELP!!
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Answer:

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3 0
3 years ago
Solve the equation... 10x - 12 = 48 - 2x
hjlf
If you would like to solve the equation 10 * x - 12 = 48 - 2 * x, you can calculate this using the following steps:

10 * x - 12 = 48 - 2 * x
10 * x + 2 * x = 48 + 12
12 * x = 60   /12
x = 60 / 12
x = 5

The correct result is 5. 
4 0
3 years ago
You earn $65,000 a year, are married, and claim your spouse, yourself, and two children. What amount is withheld weekly for fede
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C

Step-by-step explanation:

5 0
3 years ago
A coin is flipped 10 times where each flip comes up either heads or tails. How many possible outcomes (a) contain exactly two he
Tems11 [23]

Answer:

a. 45

b. 176

c. 252

Step-by-step explanation:

First take into account the concept of combination and permutation:

In the permutation the order is important and it is signed as follows:

P (n, r) = n! / (n - r)!

In the combination the order is NOT important and is signed as follows:

C (n, r) = n! / r! (n - r)!

Now, to start with part a, which corresponds to a combination because the order here is not important. Thus

 n = 10

r = 2

C (10, 2) = 10! / 2! * (10-2)! = 10! / (2! * 8!) = 45

There are 45 possible scenarios.

Part b, would also be a combination, defined as follows

n = 10

r <= 3

Therefore, several cases must be made:

C (10, 0) = 10! / 0! * (10-0)! = 10! / (0! * 10!) = 1

C (10, 1) = 10! / 1! * (10-1)! = 10! / (1! * 9!) = 10

C (10, 2) = 10! / 2! * (10-2)! = 10! / (2! * 8!) = 45

C (10, 3) = 10! / 3! * (10-3)! = 10! / (2! * 7!) = 120

The sum of all these scenarios would give us the number of possible total scenarios:

1 + 10 + 45 + 120 = 176 possible total scenarios.

part c, also corresponds to a combination, and to be equal it must be divided by two since the coin is thrown 10 times, it would be 10/2 = 5, that is our r = 5

Knowing this, the combination formula is applied:

C (10, 5) = 10! / 5! * (10-5)! = 10! / (2! * 5!) = 252

252 possible scenarios to be the same amount of heads and tails.

6 0
3 years ago
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