Answer: −4<x<1
Step-by-step explanation: plz mark brainliest
Answer:
To what
Step-by-step explanation:
Answer:
The answer is below
Step-by-step explanation:
The question is not complete. The complete question is:
The 12 foot long bed of a dump truck loaded with debris must rise an angle of 30 degrees before the debris will spill out. Approximately how high must the front of the bed rise for the debris to spill out.
Solution:
Let x be the height of the front of the bed rise needed to be raised for the debris to spill out. We can find x using trigonometric identities. That is:
sin θ = opposite / hypotenuse
Using trigonometric identities, we can get that:
sin(30) = x / 12
This gives:
0.5 = x / 12
Cross multiplying the terms to get:
x = 12 * 0.5
x = 6 ft
Therefore the front of the bed rise must be raised 6 ft for the debris to spill out.
Answer:
The drift angle is approximately 7.65° towards the East from the plane's heading
Step-by-step explanation:
The speed of the plane = 350 mph
The direction in which the plane flies N 40° E = 50° counterclockwise from the eastern direction
The speed of the wind = 40 mph
The direction of the wind = S 70° E = 20° clockwise from the eastern direction
The component velocities of the plane are;
= (350 × cos 50)·i + (350 × sin 50)·j
= (40 + cos 20)·i - (40 × sin 40)·j
The resultant speed of the plane =
+
= 265.915·i +242.404·j
The direction the plane is heading = tan⁻¹(242.404/265.915) ≈ 42.35°
Therefore, the drift angle = Actual Angle - Direction of the plane = 50 - 42.35 ≈ 7.65° towards the East