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3 years ago

Does y = -5x represent a proportional relationship?

Mathematics

1 answer:

Oduvanchick [21]3 years ago

7 0

Answer: No

Step-by-step explanation: A proportional relationship can be described by an equation of the form y = kx, where k is a number called the constant of proportionality.

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the probability of drawing a red coin after three red coins are put back in the bag to replace the blue one that has been remove

Wewaii [24]

4? I'm not sure. Just guessed.

3 0

3 years ago

What is the answer please.... need help

mina [271]

Answer:

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

$f\left(x\right)=x^3-6x^2+3x+10$

As the highest power of the x-variable is 3 with the leading coefficients of 1.

So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

$f\left(x\right)=x^3-6x^2+3x+10$

$0=x^3-6x^2+3x+10$ ∵ $f(x)=0$

$Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

$\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

Using the zero factor principle

if $ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0$

$x=-1,\:x=2,\:x=5$

Therefore, the zeros of the function are:

$x=-1,\:x=2,\:x=5$

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.

8 0

3 years ago

What is the slope of this line?

lianna [129]

The slope would be 0.

5 0

3 years ago

Read 2 more answers

Suppose you have the following information. 12% of all drivers do not have a valid driver’s license, 6% of all drivers have no i

lubasha [3.4K]

Answer:

e) 0.14

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a driver does not have a valid driver's license.

B is the probability that a driver does not have insurance.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a driver does not have a valid driver's license but has insurance and $A \cap B$ is the probability that a driver does not have any of these things.