Answer:
(A+B)(A+B)=A.A+B.A+A.B+B.B
Step-by-step explanation:
Given that matrices A and B are nxn matrices
We need to find (A+B)(A+B)
For understanding the multiplication of matrices let'take A is mxn and B is pxq matrices,we can multiple only when n=p,so our Ab matrices will be mxq.
We know that that in matrices AB is not equal to BA.
Now find
(A+B)(A+B)=A.A+B.A+A.B+B.B
So from we can say that (A+B)(A+B) is not equal to A.A+2B.A+B.B because AB is not equal to BA in matrices.
So (A+B)(A+B)=A.A+B.A+A.B+B.B
Answer:49 sec
Step-by-step explanation:
Given
Maximum speed to reach is 183.58 mi/h
Length of course is 5 mi
acceleration rate is defined by 60mi/h in 4 sec
therefore acceleration(a)


To reach a speed of 183.58mi/h with an acceleration of 
Using equation of motion
v=u+at


t=0.00339 hours
t=12.23 s reach maximum speed
To complete course it takes


t=0.01360 hour
or 
Answer:
2a^2b(5a-3b)
If not then the other way is
5a-3b
Step-by-step explanation:
The GCF of 10a^3b and -6a^2b^2 is 2a^2b
So divide by that you will get
2a^2b(5a-3b)
Answer:
26V + 2
Step-by-step explanation:
This is the same as saying f(g(x)), where x = 26
First, lets figure out what g(x) is equal to when x = 26
g(26) = V(26) - 1 = 26V - 1
Now we input 26V - 1 into f(x) for x
f(26V-1) = (26V-1) + 3 = 26V + 2