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blagie [28]
3 years ago
14

What’s the correct answer for this?

Mathematics
2 answers:
Aleksandr [31]3 years ago
5 0

Answer:

Step-by-step explanation:

52units

Lady bird [3.3K]3 years ago
5 0

Answer:

A

Step-by-step explanation:

In the attached file

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What is the volume of a hemisphere with a radius of 29 m, rounded to the nearest tenth of a cubic meter?
salantis [7]

Answer:

19.4 cubic meter

Step-by-step explanation

Round your answer to the nearest tenth of a cubic centimeter.

4 0
3 years ago
What is the probability of drawing a black ace followed by a heart out
Verdich [7]

Correct option C) 0.98%

<u>Step-by-step explanation:</u>

We know that  , there are 2 black ace cards out of 52 cards in a deck & 13 hearts out of 52 cards . Here we have to tell What is the probability of drawing a black ace followed by a heart out  of a deck when the cards aren't replaced . Let's find out:

Firstly , a black ace is drawn , so probability :

⇒ P(Black) = \frac{2}{52}

Now , A heart is drawn out of 51 cards ( as one black ace is already drawn !):

⇒ P(Heart) = \frac{13}{51}

So , Probability of occurring both events is :

⇒ P(Black)(P(Heart))

⇒ \frac{2}{52} (\frac{13}{51} )

⇒ 0.0098

Percentage = 0.0098(100) = 0.98%

Therefore , Correct option C) 0.98%

7 0
3 years ago
What is the next term of the geometric sequence? 72,36,18
MissTica

Answer:

9

Step-by-step explanation:

The ratio is 1/2 so the next term would always be half of the previous one.

- 72 times 1/2 is 36

-36 times 1/2 is 18

-18 times 1/2 is 9. So the answer is 9

5 0
3 years ago
A building 84 ft high casts a 46 ft shadow. How tall is a building that casts a 110 ft shadow at the same time of the day? (to t
Bond [772]
The ratio of building heights will be the same as the ratio of shadow lengths.
  (taller building)/(shorter building) = (longer shadow)/(shorter shadow)
  (taller building)/(84 ft) = (110 ft)/(46 ft) . . . . . . fill in the given numbers
  (taller building) = (84 ft)*(110/46) ≈ 200.9 ft . . multiply by 84 ft, evaluate

The appropriate selection is
  D) 200.9 ft
4 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B80%7D%20" id="TexFormula1" title=" \sqrt[3]{80} " alt=" \sqrt[3]{80} " ali
Marianna [84]

Start by decomposing the number inside the root into primes

Then group the terms into cubes if possible

\begin{gathered} 80=2\cdot2\cdot2\cdot2\cdot5 \\ 80=2^3\cdot2\cdot5 \\ 80=10\cdot2^3 \end{gathered}

rewrite the root

\sqrt[3]{80}=\sqrt[3]{10\cdot2^3}

then cancel the terms that are cubes and bring them out of the root

\sqrt[3]{80}=2\sqrt[3]{10}

7 0
1 year ago
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