First one,
12q^2+34q-28
divide whole thing by 2
6q^2+17q-14
use trial and error and get (2x+7)(3x-2)
factored out form is (2)(2x+7)(3x-2)
2.
divide by 3
6h^2+5h-6
trial and error and get (2x+3)(3x-2)
so the factored form is (3)(2x+2)(3x-2)
3. divide by 2
6p^2-11x-10
use trial and error and get (2x-5)(3x+2)
the factored out form is (2)(2x-5)(3x+2)
4.divide by 4
2z^2+5z-12
use trial and error and get (x+4)(2x-3)
the factored form is (4)(x+4)(2x-3)
to factor the basic thing is
ax^2+bx+c
b=x+y
ac=xy
solve for x and y
so exg 2z^2+5z-12
a=2
b=5
c=-12
2 times -12=-24
then factctor -24 and find factors that add up to 5
-1, 24
-2, 12
-3, 8
-4,6
now add
-1+24=23
-2+12=10
-3+8=5 check
-4+6=2
the numbers are -3 and 8
split it into such
2z^2+8z-3z-12
group (2z^2+8z)+(-3z-12)
undistribute using distributive property
ab+ac=a(b+c)
(2z)(z+4)+(-3)(z+4)
now reverse distribute again
((2z)+(-3))(z+4)
(2z-3)(z+4)
Answer:
c=15
8c-48+48=9c-63+48
8c=9c-15
8c-9c=9c-15-9c
\frac{-c}{-1}=\frac{-15}{-1}
c=15
Where do Christmas presents originate from? Gift giving at Christmas is a Christian tradition that is widely practiced around the world. To Christians, the gifts given at Christmas are symbolic of the tributes made to the baby Jesus by the Three Wise Men after his birth during the story of the Nativity.
Answer:
a to the -56th power, a to the 72nd power, and a squared.
Step-by-step explanation:
The answer 10 according to the given foil: