Answer:
x = 3 ±sqrt(6)
Step-by-step explanation:
6(x-3)^2-26 = 10
Add 26 to each side
6(x-3)^2-26+26 = 10+26
6(x-3)^2 = 36
Divide by 6
6/6(x-3)^2 = 36/6
(x-3)^2 = 6
Take the square root of each side
sqrt((x-3)^2) = ±sqrt(6)
x-3 = ±sqrt(6)
Add 3 to each side
x-3+3 =3 ±sqrt(6)
x = 3 ±sqrt(6)
The missing part is the proof ... hope it helped thank you you welcome have a frat day thanks bye adios amigo q to balls bin en too visa much's gracious yew me la peals pot too Ajax thanks yes what ever loll <span />
ax+r=7
Move ax to the other side. +positive ax changes to -negative ax
ax-ax+r=7-ax
r=7-ax
Answer: r=7-ax or r=-ax+7 ( same thing) but rearranged
Answer:
a = 15
b = -10
Step-by-step explanation:
Here, we want to solve the system of linear equations
Firstly, let us multiply the first equation through by 10
2a - 5b = 100 ••••(i)
from the second equation;
a = 29 + b
Substitute this into i
2(29 + b) - 5b = 100
58 + 2b -5b = 100
-3b = 100-58
3b = 42
-b = 42/3
-b = 14
recall;
a - b = 29
a - (-14) = 29
a + 14 = 29
a = 29-14 = 15
