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3 years ago

How to explain 3,482,000,000 in scientific notation

2 answers:

7 0

3.482 x 10^9.
-the coefficient must be under 10, and in this case it is the "3". Then you count the places after that to get your exponent

musickatia [10]3 years ago

5 0

3.482×10 to the 9th power

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Can you please help me out

Taya2010 [7]

The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

Total marbles (possible outcome) is,

$\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}$

Let P(R) represent the probablity of picking a red marble,

P(G) represent the probability of picking a green marble and,

P(B) represent the probability of picking a blue marble.

Probability , P, is,

$\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}$ $\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}$

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

$\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}$

Hence, the best option is G.

5 0

1 year ago

Find the maximum rate of change of f at the given point and the direction in which it occurs. f(p, q) = 8qe−p + 4pe−q, (0, 0) ma

Pachacha [2.7K]

Answer:

Step-by-step explanation:

$Given \ f (p,q) = 8qe^{-p} + 4pe^{-q} \ where \ P_o(0,0) \\ \text{thus the gradient of f is: } \\ \\ \bigtriangledown f(p,q) = \Big(\dfrac{\partial f}{\partial p}, \dfrac{\partial f}{\partial q} \Big) \\ \\ \dfrac{\partial f}{\partial p} = -8qe^{-p} + 4pe^{-q} \\ \\ \dfrac{\partial f}{\partial p} = 8qe^{-p} - 4pe^{-q} \\ \\ Then: \bigtriangledown f(p.q) = (-4qe^{-p}+ 8qe^{-q}, 4qe^{-p}- 8qe^{-q}) \\ \\ f(0,0) = (-4*(0)e^{-0}+ 8*(0)e^{-(0)}, 4*(0)e^{-(0)}- 8*(0)e^{-(0)}) \\ \\ = (0+8,4-0) = (8.4)$

$\Big| \Big | \bigtriangledown f(0,0) = \sqrt{(8)^2+4^2} \\ \\ = \sqrt{64+16} \\ \\ = \sqrt{80}$

$\mathbf{the \ direction \ of \ maximum \ change \ is }= \mathbf{\sqrt{80}} \\ \\ \mathbf{direction }(8,4)$

7 0

3 years ago

Adding which terms to 3x2y would result in a monomial? Check all that apply.

kkurt [141]

the answers are -12x^2 and 4x^2y. hopefully it helps and i just got it right.

8 0

3 years ago

Read 2 more answers

PLEASE HELP. For a field trip, a bus company charges a flat fee plus an additional fee per student. For 30 students, the total

bogdanovich [222]

Step-by-step explanation:

the change in cost of 145-135.50 = 9.50 for an increase of students from 25 to 30. The ratio of change of cost to change of students = 9.50/5 = 1.9 and becomes the slope coefficient "m" in the formula y= mx + b. y = the total cost, mx becomes the variable cost and b becomes the fixed cost. To find b, use the data point given where the total cost = $135.50 when the students = 25, or 135.50 = 1.9*25 +b. Solving for b yields $ 88. Note that the other data point is where the total cost is $145 for students = 30. Using the new total cost equation shows that 30*1.9+88= 145

3 0

3 years ago

The overhead reach distances of adult females are normally distributed with a mean of 200 cm and a standard deviation of 8.9 cm.

Advocard [28]

Answer:

0.148 or 14.80%

Step-by-step explanation:

Mean overhead reach (μ) = 200 cm

Standard deviation (σ) = 8.9 cm

The z-score for any reach, X, is given by:

$z=\frac{X-\mu}{\sigma}$

For a X = 209.30 cm:

$z=\frac{209.3-200}{8.9}\\ z=1.045$

A z-score of 1.045 corresponds to the 85.20th percentile.

Therefore, the probability that an individual distance is greater than 209.30 cm is:

$P = 1-0.8520\\P=0.148=14.80\%$

The probability is 0.148 or 14.80%

4 0

3 years ago