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ser-zykov [4K]
2 years ago
8

NEED HELP PLEASE!!! Given f(x)=9x+4 and g(x)= -5x+1, what is g(x)-f(x)?

Mathematics
1 answer:
GenaCL600 [577]2 years ago
6 0

Answer:

g(x) - f(x) = -14x - 3

Step-by-step explanation:

We need to subtract the function f(x) = 9x + 4 from the function g(x) = -5 + 1.  Rewriting these two functions in columns, we get

       g(x)= -5x+1

      - f(x) = -(9x+4)         Note:  Use parentheses as shown here.

--------------------

g(x) - f(x) = -14x - 3

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GI and JL are parallel lines.<br><br> Which angles are supplementary angles?
solmaris [256]

Answer:

The answer is A.

Step-by-step explanation:

A supplementary angles are angles that when adding both sides will sum up to 180 Degrees.

<JKH and <LKH will be the correct answer because they add up tp 180 degrees.

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6 0
3 years ago
16^3x+8^x+6<br><br>Could you please give me the steps as well for this problem? ​
BARSIC [14]

Answer:

x = 2

Step-by-step explanation:

16^{3x} = 8^{x+6} \\2^{4(3x)} = 2^{3(x+6)} --> (16 = 2^{4} and 8 = 2^{3} )

2^{12x} = 2^{3x+18}

Since the base number is 2, the exponents must equal each other.

So:

12x = 3x+18

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8 0
3 years ago
What is the volume of a right trianular prism with the dimesions of 15 11 17
Harlamova29_29 [7]

Answer:

1402.5 Cubic Units

Step-by-step explanation:

Volume of a Triangular Prism: V = \frac{1}{2}bhl

b - base

h - height

l - length  

15 is the height, 17 is the length, and 11 is the width  (assuming which is the base).

V=0.5 * (11 * 15 * 17) \\V=0.5*2085\\V=1402.5

The volume of the prism should be 1402.5 cubic units.

3 0
2 years ago
PLZZZZZ HELP ME!<br> It’s math btw
matrenka [14]

Answer:

1. 9/10

2. 15/16

4. 3/5

5. 3/5

Step-by-step explanation:

1. 7/10 + 2/10 = 9/10

2. 13/16 + 2/16 = 15/16

4. 7/15 + 2/15 = 9/15 = 3/5

5. 9/20 + 3/20 = 12/20 = 3/5

3 0
3 years ago
Read 2 more answers
Find the value of x which satisfies the following equation.<br> log2(x−1)+log2(x+5)=4
weqwewe [10]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: x = 3

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \:  log_{2}(x - 1)  log_{2}(x + 5)  = 4

\qquad \tt \rightarrow \:  log_{2} \{(x - 1)(x + 5) \} = 4

[ log (x) + log (y) = log (xy) ]

\qquad \tt \rightarrow \: ( x - 1)(x + 5) =  {2}^{4}

\qquad \tt \rightarrow \:  {x}^{2}  + 5x - x - 5 =  16

\qquad \tt \rightarrow \:  {x}^{2}  + 4x - 5 - 16 = 0

\qquad \tt \rightarrow \:  {x}^{2}  + 4x -21 = 0

\qquad \tt \rightarrow \:  {x}^{2}  + 7x - 3x - 21 = 0

\qquad \tt \rightarrow \:  x(x + 7) - 3(x + 7) = 0

\qquad \tt \rightarrow \: (x + 7)(x - 3) = 0

\qquad \tt \rightarrow \: x =  - 7 \:  \: or \:  \: x = 3

The only possible value of x is 3, since we can't operate logarithm with a negative integer in it.

\qquad \tt \rightarrow \: x = 3

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

4 0
2 years ago
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