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leva [86]
3 years ago
9

A quad-core processor can handle 1 program on each of its 4 cores at the same time. If there are 20 programs queued to run on it

, and each program can only be assigned to one core, how many different combinations of programs can be run at the same time?
Mathematics
1 answer:
Ber [7]3 years ago
5 0

Answer: N = 4845

Therefore, the number of different combinations of programs that can be run at the same time is 4845.

Step-by-step explanation:

In combination, the order of the programs does not matter.

nCr = n!/r!(n-r)!

For the case above we want to determine the number of combinations of 20 programs on a 4 cores computer.

N = 20C4 = 20!/4!(20-4)!

N = 20!/4!16!

N = (20×19×18×17×16!)/(4!×16!)

N = 4845

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STALIN [3.7K]

Answer:

x = 15

Step-by-step explanation:

the 2 angles are a linear pair and sum to 180° that is

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Geometry help needed!
salantis [7]

Answer:

AC Midpoint (2,0)-

CB Midpoint (5,-4)

midlength is 5

Step-by-step explanation:

midpoint formula (\frac{x_{1}+x_{2}  }{2} ,\frac{y_{1} +y_{2} }{2})

A(2,4) C(2,-4)

\frac{2+2}{2} =\frac{4}{2}=2\\\frac{4-4}{2}  =\frac{0}{2} =0

(2,0)

C(2,-4) B(8,-4)

\frac{8+2}{2} =\frac{10}{2} =5

\frac{-4-4}{2} =\frac{-8}{2} =-4  midpoint is  (5,-4)

Distance between the 2 midpoints is the midsegment

(2,0) and (5,-4)

d=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})  ^{2}   }

d=\sqrt{(5-2)^{2} +(-4-0)^{2}  } \\d=\sqrt{3^{2} +(-4^{2})\\ } \\d=\sqrt{x} 9+16\\d=\sqrt{25} \\d=5

3 0
3 years ago
You have 2 job offers with the following options. Option 1: You are paid $30
kozerog [31]

Answer:

It takes 6 hours for both to reach an equal paid.

Step-by-step explanation:

You have to form an expressions in terms of x where x determine the number of hours :

Option 1,

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Next, you have to compare it since they want to find out how many hours they work until they reach the same amount :

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3 years ago
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tatyana61 [14]

Answer:

Kate's electric bill will be $9 for this month for bulb use only.

Step-by-step explanation:

Given:

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Solution:

First we will find the reduction in bill after using new bulbs.

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framing in equation form we get;

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