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bonufazy [111]
3 years ago
15

A basketball player guesses her team will score 57 points during the game. The player's team actually scores 63 points. What is

the percent error in the player's guess? Round your answer to the nearest tenth of a percent. Enter your answer in the box.
Need answer ASAP!
Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
6 0

I might be wrong, but i believe the answer is 9.5

lora16 [44]3 years ago
4 0

Answer: The percent error in the player's guess is 9.5%.

Step-by-step explanation:

Given : A basketball player guesses her team will score 57 points during the game.

The player's team actually scores 63 points.

i.e. The actual core = 63 points

The estimated score = 57 points

Then , the percent error in the player's guess would be :

=\dfrac{|\text{Estimated score-Actual score}|}{\text{Actual score}}\times100\\\\=\dfrac{|57-63|}{63}\times100\\\\=\dfrac{|-6|}{63}\times100\\\\=\dfrac{6}{63}\times100=9.52380952381\%\\\\\approx9.5\%

Hence, the percent error in the player's guess is 9.5%.

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Divide both sides by -3.

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Find the sum of the geometric sequence. three divided by two, three divided by eight, three divided by thirty two, three divided
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Answer: we have that

[3/2,3/8,3/32,3/128,3/512]

the sum of the geometric sequence is [3/2+3/8+3/32+3/128+3/512]

=(1/512)*[256*3+64*3+16*3+4*3]

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the answer is

1.9922

another way to calculate it 

is through the following formula

∑=ao*[(1-r^n)/(1-r)]

where 

ao---------> is the first term

r----------> is the common ratio between terms

n----------> is the number of terms

ao=1.5

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n=5

so

∑=1.5*[(1-0.25^5)/(1-0.25)]-------------> 1.99

Step-by-step explanation: we have that

[3/2,3/8,3/32,3/128,3/512]

the sum of the geometric sequence is [3/2+3/8+3/32+3/128+3/512]

=(1/512)*[256*3+64*3+16*3+4*3]

=(3/512)*[256+64+16+4]

=(3/512)*[340]

=(1020/512)

=255/128---------> 1.9922

the answer is

1.9922

another way to calculate it 

is through the following formula

∑=ao*[(1-r^n)/(1-r)]

where 

ao---------> is the first term

r----------> is the common ratio between terms

n----------> is the number of terms

ao=1.5

r=1/4-----> 0.25

n=5

so

∑=1.5*[(1-0.25^5)/(1-0.25)]-------------> 1.99

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