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snow_tiger [21]
3 years ago
10

As a salesperson you are paid $70 per week plus $6 per sale. This week you want your pay to be at least $150. Write an inequalit

y to represent the number of sales you need to make to achieve your goal. Then solve the inequality algebraically, showing all work on your paper.
Mathematics
1 answer:
AlladinOne [14]3 years ago
7 0

<em><u>The inequality is:</u></em>

70+6x\geq 150

You must do more than 14 sales to get at least $ 150

<em><u>Solution:</u></em>

Given that,

As a salesperson you are paid $70 per week plus $6 per sale

Let "x" be the number of sales

This week you want your pay to be at least $150

We have to frame a inequality to represent the number of sales you need to make to achieve your goal

This week he must earn at least $ 150

Thus, he can spend $ 150 or more then 150 also

So we have to use "greater than or equal to" symbol

From given,

70 + 6(\text{number of sales})\geq 150

70+6x\geq 150

Thus the inequality is found

<em><u>Solve the inequality</u></em>

70+6x\geq 150\\\\Subtract\ 70\ from\ both\ sides\\\\6x\geq 150-70\\\\6x\geq 80\\\\Divide\ both\ sides\ by\ 6\\\\x\geq 13.3\\\\Thus\ approximately\ we\ get\\\\x\geq 14

So he must do more than 14 sales to get at least $ 150

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Answer:

The numbers are

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Step-by-step explanation:

Let

x -----> the smaller positive real number

y -----> the larger positive real number

we know that

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so

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When 4 times the larger is added to the square of the smaller, the result is 49

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substitute equation A in equation B

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solve for x

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The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^2+4x-41=0

so

a=1\\b=4\\c=-41

substitute in the formula

x=\frac{-4\pm\sqrt{4^{2}-4(1)(-41)}} {2(1)}

x=\frac{-4\pm\sqrt{180}} {2}

x=\frac{-4\pm6\sqrt{5}} {2}

x=-2\pm3\sqrt{5}

so

The positive real number is

x=-2+3\sqrt{5}

Find the value of y

y=x+2

y=-2+3\sqrt{5}+2

y=3\sqrt{5}

6 0
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Answer:

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