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snow_tiger [21]
3 years ago
10

As a salesperson you are paid $70 per week plus $6 per sale. This week you want your pay to be at least $150. Write an inequalit

y to represent the number of sales you need to make to achieve your goal. Then solve the inequality algebraically, showing all work on your paper.
Mathematics
1 answer:
AlladinOne [14]3 years ago
7 0

<em><u>The inequality is:</u></em>

70+6x\geq 150

You must do more than 14 sales to get at least $ 150

<em><u>Solution:</u></em>

Given that,

As a salesperson you are paid $70 per week plus $6 per sale

Let "x" be the number of sales

This week you want your pay to be at least $150

We have to frame a inequality to represent the number of sales you need to make to achieve your goal

This week he must earn at least $ 150

Thus, he can spend $ 150 or more then 150 also

So we have to use "greater than or equal to" symbol

From given,

70 + 6(\text{number of sales})\geq 150

70+6x\geq 150

Thus the inequality is found

<em><u>Solve the inequality</u></em>

70+6x\geq 150\\\\Subtract\ 70\ from\ both\ sides\\\\6x\geq 150-70\\\\6x\geq 80\\\\Divide\ both\ sides\ by\ 6\\\\x\geq 13.3\\\\Thus\ approximately\ we\ get\\\\x\geq 14

So he must do more than 14 sales to get at least $ 150

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sergeinik [125]

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

<h3>¿Cómo determinar la medida de un lado de un triángulo desconocido?</h3>

En este problema tenemos un sistema formado por dos triángulos <em>similares</em>, la semejanza entre los dos triángulos se debe a la colinealidad entre los segmentos de línea AP' (triángulo <em>pequeño</em>) y AP'' (triángulo <em>grande</em>), así como de los lados AM y AB, así como los lados AN y AC, así como los <em>mismos</em> ángulos en la <em>misma</em> distribución. (Semejanza Lado - Ángulo - Lado)

En consecuencia, obtenemos las siguientes proporciones:

AP'/AP'' = MN/BC = 1/2     (1)

Finalmente, la proporción entre el triángulo AMN y el cuadrilátero BMNC es:

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)}{\frac{1}{2}\cdot (2\cdot a) \cdot  h - \frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)} = \frac{\frac{1}{4}\cdot a\cdot h }{a\cdot h - \frac{1}{4}\cdot a \cdot h }

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{4} }{\frac{3}{4} } = \frac{1}{3}

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

Para aprender sobre triángulos semejantes: brainly.com/question/21730013

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