Completed question:
In the game of tic-tac-toe, if all moves are performed randomly the probability that the game will end in a draw is 0.127. Suppose six random games of tic-tac-toe are played. What is the probability that at least one of them will end in a draw?
Answer:
0.557
Step-by-step explanation:
For each game, the probability of not end in a draw is 1 - 0.127 = 0.873. Thus, because each game is independent of each other, the probability of all of them not end in a draw is the multiplication of the probability of each one:
0.873x0.873x0.873x...x0.873 = 0.873⁶ = 0.443
Thus, the probability that at least one of them end in a draw is the total probability (1) less the probability that none of them en in a draw:
1 - 0.443
0.557
19.83 x 1.07 = <span>21.218
$21.22</span>
Answer:
-$200
Step-by-step explanation:
Given that:
Net earning per bouquet for the month= - $2.50
On a particular day of the month, 20 bouquet was sold ;
Net earning for the day:
Net earning per bouquet * number of bouquet
-$2.50 * 80
= $200
Hence, net earning for Tuesday = - $200
Answer:
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Step-by-step explanation:
