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Irina18 [472]
3 years ago
12

How can I solve this problem?

Mathematics
1 answer:
HACTEHA [7]3 years ago
7 0

Answer:

25*pi or

78.5 square units.

Step-by-step explanation:

If there was no shaded area, the area of the circle would be pi * r^2

r = 10

Area = pi * 10^2

Area = 100 * pi

Since there is a shaded area, the shaded part looks to be 1/4 of the whole. There's no indication of what it actually is, but 1/4 should be close enough.

Area_shade = 1/4 (100*pi)

Area_shade = 25 * pi

That's one answer.

Another is 25 * 3.14 = 78.5 square units

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nika2105 [10]
18;45 = 9

24;16 = 8

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8 0
3 years ago
Solve for x…..…………………
anzhelika [568]

Answer:

x = 11

Step-by-step explanation:

From the diagram, we find,

(2x - 16) + (x - 8) = 9

=> 2x - 16 + x - 8 = 9

=> 2x + x - 16 - 8 = 9

=> 3x - 24 = 9

=> 3x = 9 + 24

=> 3x = 33

=> x = 33/3

=> x = 11

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2 years ago
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In the coordinate plane, the directed line segment from K to N has endpoints at K(–6, –2) and N(8, 3). Point L partitions the di
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A builder wants to build the bridge whose cross section is shown in the diagram. Two companies offer simple bids on building the
leva [86]

The length of the bridge is the distance from the beginning to the end.

<em>The distance b between each beam is 9ft.</em>

Let:

<em />I \to<em> I-Beam</em>

<em />d_I \to<em> distance between I beam and the bridge</em>

<em />b \to<em> distance between each I beam</em>

<em />

Given that:

I = \frac 34 ft\\

d_I = 3 ft

<em />Length = 55ft\ 6in<em> --- length of the  bridge</em>

<em />

From the diagram (see attachment), there are: 6 I-beams.

So, the length of the 6 I-beams is:

L_1 = 6 \times I

L_1 = 6 \times \frac 34

L_1 = \frac {18}4

L_1 = 4.5ft

There are 2 I-beams beside the bridge

So, the distance between the 2 I-beams and the bridge is:

d_1 =2 \times d_I

d_1 =2 \times 3ft

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There are 5 spaces between the I-beams

So, the length of the total spaces is:

L_2 = 5 \times b

L_2 = 5b

The total length is:

Length = L_1 + d_1 + L_2

So, we have:

4.5ft + 6ft + 5b = 55ft\ 6in

Collect like terms

5b = 55ft\ 6in - 4.5ft - 6ft

5b = 44.5ft\ 6in

Convert inches to feet

5b = 44.5ft\ + \frac{6}{12}ft

5b = 44.5ft\ + 0.5ft

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Divide both sides by 5

b = 9ft

<em>Hence, the distance (b) between each beam is 9ft.</em>

Read more about lengths at:

brainly.com/question/22059747

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